Thực hiện phép tính − 3 2 + 2 3 − − 5 2 + 4 3
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\(a,2010:\left(-5\right)+400-1\\ =-402+400-1\\ =-3\\ b,\dfrac{2}{3}+\dfrac{3}{4}.\left(-\dfrac{4}{9}\right)\\ =\dfrac{2}{3}-\dfrac{1}{3}\\ =\dfrac{1}{3}\\ c,\left(1-\dfrac{2}{3}-\dfrac{1}{4}\right)\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\\ =\dfrac{1}{12}.\left(\dfrac{1}{20}\right)^2\\ =\dfrac{1}{12}.\dfrac{1}{400}\\ =\dfrac{1}{4800}\)
a) \(2010:\left(-5\right)+400-1=-400+400-1=-1\)
b) \(\dfrac{2}{3}+\dfrac{3}{4}\cdot\dfrac{-4}{9}=\dfrac{2}{3}+\dfrac{-1}{3}=\dfrac{1}{3}\)
c) \(\left(1-\dfrac{2}{3}-\dfrac{1}{4}\right)\cdot\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2=\dfrac{1}{12}\cdot\dfrac{1}{400}=\dfrac{1}{4800}\)
1, 3/5 + -4/15 = \(\dfrac{9}{15}\)+ \(\dfrac{-4}{15}\)= \(\dfrac{5}{15}\)= \(\dfrac{1}{3}\)
2, -1/3 + 2/5 + 2/15= \(\dfrac{-5}{15}+\dfrac{6}{15}+\dfrac{2}{15}\)=\(\dfrac{3}{15}=\dfrac{1}{5}\)
3, -3/5 + 7/21 + -4/5 + 7/5= \(\dfrac{1}{3}\)
\(1.\dfrac{3}{5}+\dfrac{-4}{15}=\dfrac{9}{15}+\dfrac{-4}{15}=\dfrac{5}{15}=\dfrac{1}{3}\)
\(2.\dfrac{-1}{3}+\dfrac{2}{5}+\dfrac{2}{15}=\dfrac{-5}{15}+\dfrac{6}{15}+\dfrac{2}{15}=\dfrac{3}{15}=\dfrac{1}{5}\)
\(3.\dfrac{-3}{5}+\dfrac{7}{21}+\dfrac{-4}{5}+\dfrac{7}{5}=\left(\dfrac{-3}{5}+\dfrac{-4}{5}+\dfrac{7}{5}\right)+\dfrac{7}{21}=0+\dfrac{7}{21}=\dfrac{1}{3}\)
\(\frac{1}{4}.\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right)\div3\frac{2}{3}\)
\(=\frac{15}{196}-\left(\frac{12}{15}+\frac{10}{15}\right)\div\frac{11}{3}\)
\(=\frac{15}{196}-\left(\frac{12}{15}+\frac{10}{15}\right).\frac{3}{11}\)
\(=\frac{15}{196}-\frac{22}{15}.\frac{3}{11}\)
\(=\frac{15}{196}-\frac{2}{5}.\frac{1}{1}\)
\(=\frac{15}{196}-\frac{2}{5}\)
\(=\frac{75}{980}-\frac{392}{980}=\frac{-317}{980}\)
\(\frac{1}{4}\cdot\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right):3\frac{2}{3}\)
\(=\frac{15}{196}-\frac{22}{15}\cdot\frac{3}{11}\)
\(=\frac{15}{196}-\frac{2}{5}\)
\(=-\frac{317}{980}\)
− 3 2 + 2 3 − − 5 2 + 4 3 = 9 + 8 – 25 + 64 = 56