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\(a,\dfrac{6}{11}+6+\dfrac{5}{7}=\dfrac{42+462+55}{77}=\dfrac{559}{77}\)
\(b,\dfrac{9}{8}\times\dfrac{3}{12}:\dfrac{5}{9}=\dfrac{9}{8}\times\dfrac{3}{12}\times\dfrac{9}{5}=\dfrac{243}{480}=\dfrac{81}{160}\)
\(c,\dfrac{8}{7}:4+2=\dfrac{8}{7}\times\dfrac{1}{4}+2=\dfrac{8}{28}+2=\dfrac{2}{7}+2=\dfrac{16}{7}\)
\(d,\dfrac{3}{5}+4:\dfrac{6}{4}=\dfrac{3}{5}+4\times\dfrac{4}{6}=\dfrac{3}{5}+\dfrac{8}{3}=\dfrac{49}{15}\)
a, 2/3 - 2/9 + 7/9 = 6/9 - 2/9 + 7/9 = 10/9
b, 7/6 + 3/5 : 6 = 7/6 + 3/5 x 1/6 = 7/6 + 1/10 = 70/60 + 6/10 = 76/10 = 38/5
c, x : 6/25 = 18
x = 18 x 6/25
x = 36/25
d, ( 2/5 + 4/7) : x = 17/5
29/35 : x = 17/5
x = 29/35 : 17/5
x = 29/119
\(a.\dfrac{2}{3}-\dfrac{2}{9}+\dfrac{7}{9}=\dfrac{6}{9}-\dfrac{2}{9}+\dfrac{7}{9}=\dfrac{4}{9}+\dfrac{7}{9}=\dfrac{11}{9}\\ b.\dfrac{7}{6}+\dfrac{3}{5}:6=\dfrac{7}{6}+\dfrac{3}{5}\times\dfrac{1}{6}=\dfrac{7}{6}+\dfrac{1}{10}=\dfrac{70}{60}+\dfrac{6}{60}=\dfrac{76}{60}=\dfrac{19}{15}\\ c.x:\dfrac{6}{25}=18\\ x=18\times\dfrac{6}{25}\\ x=\dfrac{108}{25}\\ d.\left(\dfrac{2}{5}+\dfrac{4}{7}\right):x=\dfrac{17}{5}\\ \dfrac{34}{35}:x=\dfrac{7}{5}\\ x=\dfrac{34}{35}:\dfrac{7}{5}\\ x=\dfrac{34}{49}\)
1080 - a: 6 = 568
=> a : 6 = 1080 - 568
a : 6 = 512
a = 512 x 6
a = 3072
ta có : 1080-a :6 = 568
=> a : 6 = 1080 - 568
=> a : 6 = 512
=> a = 512 . 6
=> a= 3072
\(x+\dfrac{1}{5}-\dfrac{3}{7}=\dfrac{6}{35}\)
\(x+\dfrac{1}{5}=\dfrac{6}{35}+\dfrac{3}{7}\)
\(x+\dfrac{1}{5}=\dfrac{6}{35}+\dfrac{15}{35}\)
\(x+\dfrac{1}{5}=\dfrac{21}{35}\)
\(x=\dfrac{21}{35}-\dfrac{1}{5}\)
\(x=\dfrac{21}{35}-\dfrac{7}{35}\)
\(x=\dfrac{14}{35}=\dfrac{2}{5}\)
\(x\) + \(\dfrac{1}{5}\) - \(\dfrac{3}{7}\) = \(\dfrac{6}{35}\)
\(x\) + \(\dfrac{1}{5}\) = \(\dfrac{6}{35}\) + \(\dfrac{3}{7}\)
\(x\) + \(\dfrac{1}{5}\) = \(\dfrac{3}{5}\)
\(x\) = \(\dfrac{3}{5}\) - \(\dfrac{1}{5}\)
\(x\) =\(\dfrac{2}{5}\)
giải hộ mik với nhaaaa !!!
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