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\(4x^2-6x-16⋮x-3\)
\(\Leftrightarrow4x^2-12x+6x-18+2⋮x-3\)
\(\Leftrightarrow4x\left(x-3\right)+6\left(x-3\right)+2⋮x-3\)
\(\Leftrightarrow\left(x-3\right)\left(4x+6\right)+2⋮x-3\)
Mà \(\left(x-3\right)\left(4x+6\right)⋮x-3\)
\(\Rightarrow2⋮x-3\)
\(\Rightarrow x-3\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)
làm nốt
cách 2:
Để \(4x^2-6x-16\)chia hết cho x-3
\(\Leftrightarrow2⋮x-3\)
\(\Leftrightarrow x-3\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)
Làm nốt
bn ơi cho mk hỏi bn lm tiếng anh hay toán mà chủ đề là tiếng anh mà bài lại là toán vậy alo????
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a) a^2 (x-y) +y-x
= a^2 (x-y) -(x-y)
= (x-y) (a^2 -1)
= (x-y)(a-1)(a+1)
b) m^2 -25y^2+10y -1
= m^2 -(25y^2 -10y +1)
= m^2-(5y-1)^2
=(m-5y+1)(m+5y-1)
c) a^2 -4x^2 +8x -4
= a^2 -(4x^2 -8x+4)
=a^2 -( 2x-2)^2
=(a-2x+2)(a+2x-2)
mik nhầm môn
TA à