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x : 5 + 1 +3 + 5 = 135
=> x : 5 + 9 = 135
=> x : 5 = 135 - 9
=> x :5 = 126
=> x = 126 x 5
=> x= 630
\(x+\dfrac{1}{5}-\dfrac{3}{7}=\dfrac{6}{35}\)
\(x+\dfrac{1}{5}=\dfrac{6}{35}+\dfrac{3}{7}\)
\(x+\dfrac{1}{5}=\dfrac{6}{35}+\dfrac{15}{35}\)
\(x+\dfrac{1}{5}=\dfrac{21}{35}\)
\(x=\dfrac{21}{35}-\dfrac{1}{5}\)
\(x=\dfrac{21}{35}-\dfrac{7}{35}\)
\(x=\dfrac{14}{35}=\dfrac{2}{5}\)
\(x\) + \(\dfrac{1}{5}\) - \(\dfrac{3}{7}\) = \(\dfrac{6}{35}\)
\(x\) + \(\dfrac{1}{5}\) = \(\dfrac{6}{35}\) + \(\dfrac{3}{7}\)
\(x\) + \(\dfrac{1}{5}\) = \(\dfrac{3}{5}\)
\(x\) = \(\dfrac{3}{5}\) - \(\dfrac{1}{5}\)
\(x\) =\(\dfrac{2}{5}\)
2/3 = 2 x 4/ 3 x 4 =8/12
8/14 = 8 : 2/ 14 : 2 =4/7
5/9 = 5 x3/ 9 x 3 =15/37
35/ 40 = 35 : 5/ 40 : 5=7/8
Ta có : \(\frac{5}{7}=\frac{x}{63}\)
\(\Rightarrow\) \(\frac{45}{63}=\frac{x}{63}\)
\(\Rightarrow\) \(x=45\)
Vậy x = 45
Cbht !!! ❤️❤️❤️
\(\frac{5}{7}=\frac{x}{63}\\ \Leftrightarrow5\times63=7x.\)
\(\Leftrightarrow315=7x\)
\(\Leftrightarrow x=45\)