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\(=\left(x+2\right)^3+y^3\)
\(=\left(x+2+y\right)\left(x^2+4x+4-xy-2y+y^2\right)\)
\(12x-9-4x^2=-\left(2x-3\right)^2\\ Sửa:x^3-6x^2y+12xy^2-8y^3=\left(x-2y\right)^3\)
=(x^3+6x^2+12x+8)+y^3
=(x^3+3x^2+3x2^2+2^3)+y^3
=(x+2)^3+y^3
=(x+2+y)((x+2)^2-(x+2)y+y^2)
=(x+2+y)(x^2+4x+4-xy-2y+y^2)
=(x+2+y)(x^2+y^2-xy+4x-2y+4)
x3 - 6x2 + 12x - 8
= x3 - 2x2 - 4x2 + 4x + 8x - 8
= (x3 - 2x2) - (4x2 - 8x) + (4x - 8)
= x2.(x - 2) + 4x.(x - 2) + 4.(x - 2)
= (x - 2).(x2 + 4x + 4)
= (x - 2).(x2 + 2x + 2x + 4)
= (x - 2).[x.(x + 2) + 2.(x + 2)]
= (x - 2).(x + 2).(x + 2)
= (x - 2).(x + 2)2
\(=6x\left(-y^2+x^2+2x+1\right)\\ =6x\left[\left(x^2+2x+1\right)-y^2\right]\\ =6x\left[\left(x+1\right)^2-y^2\right]\\ =6x\left(x+1-y\right)\left(x+1+y\right)\)
\(=\left(x+2\right)^3+y^3\)
\(=\left(x+2+y\right)\left(x^2+4x+4-xy-2y+y^2\right)\)
\(x^3+y^3+6x^2+12x+8\)
=\(x^3+3.2.x^2+3.2^2.x+2^3+y^3\)
\(=\left(x+2\right)^3+y^3=\left(x+2+y\right)\left(\left(x+2\right)^2-\left(x+2\right)y+y^2\right)\)
\(=\left(x+y+2\right)\left(x^2+4x+4-xy-2y-y^2\right)\)
x3 - 6x2 + 12x - 8
= x3 - 2x2 - 4x2 + 4x + 8x - 8
= (x3 - 2x2) - (4x2 - 8x) + (4x - 8)
= x2.(x - 2) + 4x.(x - 2) + 4.(x - 2)
= (x - 2).(x2 + 4x + 4)
= (x - 2).(x2 + 2x + 2x + 4)
= (x - 2).[x.(x + 2) + 2.(x + 2)]
= (x - 2).(x + 2).(x + 2)
= (x - 2).(x + 2)2
\(x^4-6x^3+12x^2-14x+3\)
= \(x^4-4x^3+x^2-2x^3+8x^2-2x+3x^2-12x+3\)
= \(x^2\left(x^2-4x+1\right)-2x\left(x^2-4x+1\right)+3\left(x^2-4x+1\right)\)
= \(\left(x^2-4x+1\right)\left(x^2-2x+3\right)\)
\(=\left(x^3-6x^2+12x-8\right)+1\\ =\left(x-2\right)^3+1\\ =\left(x-2+1\right)\left(x^2-4x+4-x+2+1\right)\\ =\left(x-1\right)\left(x^2-5x+7\right)\)