Question

[TBQT]

lam bai sau

https://drive.google.com/file/d/1JcZ1y4xa1qA2CbhKPy3MTvQYQ4Rr5TIq/view

Answer 1

[ღ๖ۣۜLinh's ๖ۣۜLinh'sღ] ★we are one★]

\(a,\frac{2x+1}{x-1}=\frac{5\left(x-1\right)}{x+1}\)

\(ĐK:x\ne\pm1\)

\(PT\Leftrightarrow\left(2x+1\right)\left(x-1\right)=5\left(x-1\right)^2\)

\(\Leftrightarrow2x^2-x-1=5\left(x^2-2x+1\right)\)

\(\Leftrightarrow3x^2-9x+4=0\)

\(\Leftrightarrow3\left(x^2-2.\frac{3}{2}x+\frac{9}{4}\right)=\frac{11}{4}\)

\(\Leftrightarrow\left(x-\frac{3}{2}\right)^2=\frac{11}{12}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\sqrt{\frac{11}{12}}+\frac{3}{2}\\x=-\sqrt{\frac{11}{12}}+\frac{3}{2}\end{cases}}\)