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Giải biểu thức sau:
(1/7+1/91+1/24+1/475).25/24.x+30%=1/2
(1/6+1/66+1/176+1/336+1/546).26/25.x+30%=1/2
\(D=\frac{1}{6}+\frac{1}{66}+\frac{1}{176}+\frac{1}{336}+\frac{1}{546}\)
\(D=\frac{1}{1.6}+\frac{1}{6.11}+\frac{1}{11.16}+\frac{1}{16.21}+\frac{1}{21.26}\)
\(D=\frac{1}{5}\left(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+\frac{5}{16.21}+\frac{5}{21.26}\right)\)
\(D=\frac{1}{5}\left(\frac{1}{1}-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{21}-\frac{1}{26}\right)\)
\(D=\frac{1}{5}\left(\frac{1}{1}-\frac{1}{26}\right)\)
\(D=\frac{1}{5}.\frac{25}{26}=\frac{5}{26}\)
1/6+1/66+1/176+....+1/496.501
=1/1.6+1/6.11+1/11.16+....+1/496.501
=(1/5).(5/1.6+5/6.11+5/11.16+....+5/496.501)
=(1/5).(1-1/6+1/6-1/11+1/11-1/16+...+1/496-1/501)
=(1/5).(1-1/501)
=1/5 . 500/501
=100/501
Ta có: 1/6+1/66+1/176+1/336+...+1/496.501
=1/1.6+1/6.11+1/11.16+1/16.21+...+1/496.501
=1/5.(5/1.6+5/6.11+5/11.16+5/16.21+...+5/496.501)
=1/5.(1-1/6+1/6-1/11+1/11-1/16+1/16-1/21+...+1/496-1/501)
=1/5.(1-1/501)
=1/5.500/501
=100/501
\(B=\frac{1}{1.6}+\frac{1}{6.11}+\frac{1}{11.16}+\frac{1}{16.21}+...+\frac{1}{496.501}\)
=> \(B=\frac{1}{5}.\left(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+\frac{5}{16.21}+...+\frac{5}{496.501}\right)\)
=> \(B=\frac{1}{5}.\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+...+\frac{1}{496}-\frac{1}{501}\right)\)
=> \(B=\frac{1}{5}.\left(1-\frac{1}{501}\right)=\frac{1}{5}.\frac{500}{501}=\frac{100}{501}\)
\(\frac{5113}{25168}\)
Chúc bạn học tốt !!!