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<1/25+1/25+...+1/25+1/40+1/40+1/40+...+1/40
=1/25.15+1/40.15=15/25+15/40=3/5+3/8=39/40
đặt vế trái là A ta có A<1/25.16+1/45.14=214/225=1-11/225 39/40=1-1/40 ta có 1.225<11.40=>1/40<11/225=>1-1/40>1-11/225=>214/225<39/40 mà A<214/225=>A<39/40(đpcm nhớ k cho mk nha
\(a.17+26:2\\ =17+13\\ =30\\ b.300:\left[130-6\left(45-40\right)\right]\\ =300:\left[130-6.5\right]\\ =300:\left[130-30\right]\\ =300:100\\ =3\\ c.\left(-15\right).\left(-2\right)\\ =15.2\\ =30\\ d.\left(-27\right).36+54.\left(-27\right)\\ =\left(-27\right)\left(36+54\right)\\ =\left(-27\right).90\\ =-2430\)
a) 17+14=31
b) 300:[130-6.5)
300:[130-30]
300:100
3
c)30
d)(36+54).(-27)
=90.(-27)
=-2430
\(a,2^2=4,2^3=8,2^4=16,2^5=32,2^6=64,2^7=128,2^8=256,2^9=512,2^{10}=1024\)
\(b,3^2=9,3^3=27,3^4=81,3^5=243\)
\(c,4^2=16,4^3=64,4^4=256\)
\(d,5^2=25,5^3=125,5^4=625\)
Bài 1: Tính
a) (−14) + (− 28) = -42 b) ( −26) + 47= 21 c) 35 + (− 63) = -28
d) ( −8) +12 +( −24)= -20 e) ( −26)−27= -53 f) ( −35)− ( −105)=70
Bài 2: Tính hợp lý
a) 54 +(12+ 46)= 112 b) 157− (200+57) =-100
c) (− 34) [(− 34)+2020]=(-34)+1986=1952
d) 45− (137− 155)=63 e) 27− 8− 12− 7 =0
f) ( −72)+26 −28− 6 =-80
ta có B <1
suy ra B=\(\frac{5^{26}+1}{5^{27}+1}\)<\(\frac{5^{26}+1+4}{5^{27}+1+4}\)<\(\frac{5^{26}+5}{5^{27}+5}\)=\(\frac{5\cdot\left(5^{25}+1\right)}{5\cdot\left(5^{26}+1\right)}\)=\(\frac{5^{25}+1}{5^{26}+1}\)=A
Vậy B<A
k cho mk nha
Ta có : 1/25 + 1/26 + 1/27 +.....+1/39 < 1/25 + 1/25 + .....+1/25 = 15/25 = 3/5
1/40+1/41 +.....+1/54 < 1/40 + 1/40 +....+1/40 = 15/40 = 3/8
=> A = 1/25 + 1/26 + 1/27 +.......+1/54 < 3/5 + 3/8 = 39/40
=> A < 39/40 (đpcm)