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nFe = \(\frac{5,6}{56}\) = 0,1 mol
nCu =\(\frac{3,2}{64}\) = 0,05 mol
nHNO3 = 0,5 . 0,2 = 0,1 mol
nHCl = 0,5 . 0,8 = 0,4 mol
nH+ = nHNO3 + nHCl = 0,5 mol
nCl- = nHCl = 0,4 mol
\(Fe,Cu\underrightarrow{+H^+,NO3^-,Cl^-}Fe^{2+},Cu^{2+},H^+Cl^-\underrightarrow{+Ag^+,NO3^-}\left\{{}\begin{matrix}Fe^{3+},Cu^{2+}\\Ag,AgCl\end{matrix}\right.\)
Fe0 → Fe+3 + 3e.....................4H+ + NO3- + 3e → NO + H2O
0,1________0,3......................0,5__________0,375
Cu0 → Cu+2 + 2e......................................Ag+ + 1e → Ag
0,05_________0,1..............................................x___x
BT e: 0,3 + 0,1 = 0,375 + x
→ x = 0,025
Ag+ + Cl- → AgCl
______0,4____0,4
m↓ = mAg + mAgCl
= 0,025 . 108 + 0,4 . 143,5
= 60,1 (g)
\(2CH_4^{\left[A\right]}\xrightarrow[1500^{\circ}C]{lln}C_2H_2^{\left[B\right]}+2H_2^{\left[C\right]}\)
\(C_2H_2^{\left[B\right]}+2AgNO_3+2NH_3\xrightarrow[]{}2NH_4NO_3^{\left[E\right]}+C_2Ag_2^{\left[D\right]}\downarrow\)
\(C_2Ag_2^{\left[D\right]}+2HCl^{\left[F\right]}\xrightarrow[]{}C_2H_2^{\left[B\right]}+2AgCl^{\left[G\right]}\downarrow\)
\(2C_2H_2^{\left[B\right]}\xrightarrow[t^\circ]{NH_4Cl,CuCl}CH\equiv C-CH=CH_2^{\left[H\right]}\)
\(CH\equiv C-CH=CH_2^{\left[H\right]}+H_2^{\left[C\right]}\xrightarrow[t^\circ]{Pd\text{ / }PbCO_3}CH_2=CH-CH=CH_2^{\left[I\right]}\)
\(nCH_2=CH-CH=CH_2\xrightarrow[t^{\circ},p]{xt}\left(-CH_2-CH=CH-CH_2\right)_n^{\left[-\left(I\right)_n-\right]}\)
Gọi tên:
(A): Metan
(B): Axetylen
(C): Hiđro
(D): Bạc axetylua
(E): Amoni nitrat
(F): Axit clohiđric
(G): Bạc clorua
(H): Vinylaxetylen
(I): Buta-1,3-đien
-(I)n-: Cao su buna
\(A:CH_4;B:C_2H_2;C:H_2\\ D:C_2Ag_2;E:NH_4NO_3\\ F:HCl;G:AgCl\\H:C_4H_4;I:C_4H_6\\ 2CH_4-^{1500^0C,làm.lạnh.nhanh}->C_2H_2+3H_2\\ C_2H_2+2AgNO_3+2NH_3->C_2Ag_2+2NH_4NO_3\\ C_2Ag_2+2HCl->2AgCl+C_2H_2\\ 2C_2H_2-^{CuCl_2,NH_4Cl,100^0C}->H_2C=CH-C\equiv CH\\ H_2C=CH-C\equiv CH+H_2-^{Pd.PbCO_3,t^0}->H_2C=CH-CH=CH_2\\ H_2C=CH-CH=CH_2-^{t^0,p,xt}->-\left(H_2C-CH=CH-CH_2\right)-_n\)