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1) 15:(x+2) = 3
x + 2 = 15 : 3
x + 2 = 5
x = 5 - 2
x = 3
2) 20:(1+x) = 2
1 + x = 20 : 2
1 + x = 10
x = 10 - 1
x = 9
3) 5(x+35) = 515
x + 35 = 515 : 5
x + 35 = 103
x = 103 - 35
x = 68
4) 541+(218-x) = 73
218 - x = 73 - 541
218 - x = -468
x = 218 - ( - 468 )
x = 686
5) 1230:3 (x-20) = 10
410 . ( x - 20 ) = 10
x - 20 = 10 : 410
x - 20 = 1/41
x = 1/41 + 20
x = 821/41
6) 48-3(x+5) = 24
3( x + 5 ) = 48 - 24
3( x + 5 ) = 24
x + 5 = 24 : 3
x + 5 = 8
x = 8 - 5
x = 3
7) 4x + 18 : 2=13
4x + 9 = 13
4x = 13 - 9
4x = 4
x = 1
8) X-48:16 = 37
x - 3 = 37
x = 37 + 3
x = 40
a, 15: (x+2) = 3
x+2 =15:3
x+2 = 5
x = 5-2
x = 3
b, 20: (1+x) = 2
1+x = 20:2
1+x = 10
x = 10-1
x = 9
c, 5(x+35) = 515
x+35 = 515 :5
x+35 = 103
x = 103-35
x = 68
d, 541+ (218-x) = 73
218-x = 73-541
218-x = - 468
x = 218 - (-468)
x = 218 + 468
x = 686
e, 1230:3. (x-20) = 10
410(x-20) = 10
x-20 = 10: 410
x-20 = 1/41
x = 1/41 + 20
x = 821/41
f, 48-3(x+5) = 24
3(x+5) = 48-24
3(x+5) = 24
x+5 = 24:3
x +5 = 8
x = 8-5
x =3
g, 4x + 18 : 2 = 13
4x + 9 = 13
4x = 13-9
4x = 4
x = 4:4
x = 1
j, x - 48:16 = 37
x- 3 = 37
x = 37+3
x = 40
\(a,\Rightarrow2x-25=33\\ \Rightarrow2x=58\\ \Rightarrow x=29\\ b,\Rightarrow x+35=103\\ \Rightarrow x=68\\ c,\Rightarrow4^{x+1}=4^3\\ \Rightarrow x+1=3\\ \Rightarrow x=2\\ d,\Rightarrow x-235=865\\ \Rightarrow x=1100\)
a) Ta có: x-43=(35-x)-48
⇔x-43=35-x-48
⇔x-43=-x-13
⇔x-43+x+13=0
⇔2x-30=0
⇔2(x-15)=0
mà 2≠0
nên x-15=0
hay x=15
b) Ta có: 305-x+14=48+(x-23)
⇔319-x=48+x-23
⇔319-x=x+25
⇔319-x-x-25=0
⇔-2x+294=0
⇔-2x=-294
hay x=147
Vậy: x=147
c) Ta có: -(x-6+85)=(x+51)-54
⇔-x+6-85=x+51-54
⇔-x-79=x-3
⇔-x-79-x+3=0
⇔-2x-76=0
⇔-2x=76
hay x=-38
Vậy: x=-38
d) Ta có: -(35-x)-(37-x)=33-x
⇔-35+x-37+x-33+x=0
⇔3x-105=0
⇔3(x-35)=0
mà 3≠0
nên x-35=0
hay x=35
Vậy: x=35
e) Ta có: 13-|x|=|-4|
⇔13-|x|=4
⇔|x|=9
⇔x∈{9;-9}
Vậy: x∈{9;-9}
f) Ta có: |x|-3+6=16
⇔|x|+3=16
⇔|x|=13
hay x∈{-13;13}
Vậy: x∈{-13;13}
g) Ta có: 35-|2x-1|=14
⇔|2x-1|=21
⇔\(\left[{}\begin{matrix}2x-1=21\\2x-1=-21\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=22\\2x=-20\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=11\\x=-10\end{matrix}\right.\)
Vậy: x∈{11;-10}
h) Ta có: |3x-2|+5=9-x
⇔|3x-2|+5-9+x=0
⇔|3x-2|-4+x=0
⇔|3x-2|=0-(-4+x)
⇔|3x-2|=4-x
⇔\(\left[{}\begin{matrix}3x-2=4-x\\3x-2=x-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}3x-2-4+x=0\\3x-2-x+4=0\end{matrix}\right.\)\(\Leftrightarrow\left[{}\begin{matrix}4x-6=0\\2x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x=6\\2x=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{3}{2}\left(ktm\right)\\x=-1\left(tm\right)\end{matrix}\right.\)
Vậy: x=-1
\(-16+24+16-34=\left(24-34\right)+\left(16-16\right)=-10\\ 25+37-48-25-37=\left(25-25\right)+\left(37-37\right)-48=-48\\ 2575+37-2576-29=\left(2575-2576\right)+\left(37-29\right)=-1+6=5\\ 34+35+36+37-14-15-16-17=\left(34-14\right)+\left(35-15\right)+\left(36-16\right)+\left(37-17\right)=0\)
(-16)+24+16-34=24-34=-10
25+37-48-25-37=(25-25)+(37-37)-48=-48
2575+37-2576-29=8-1=7
34+35+36+37-14-15-16-17
=(34-14)+(35-15)+(36-16)+(37-17)
=20+20+20+20=20.4=80
\(2x-20=35:33\)
\(\Rightarrow2x-20=35.\dfrac{1}{33}\)
\(\Rightarrow2x=\dfrac{35}{33}+20\)
\(\Rightarrow2x=\dfrac{695}{33}\)
\(\Rightarrow x=\dfrac{695}{33}:2\)
\(\Rightarrow x=\dfrac{695}{66}\)