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Question

(-7/23).(13/28)+(-7/23).(25/28)
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YangSu · Accepted Answer

$\left(-\dfrac{7}{23}\right).\left(\dfrac{13}{28}\right)+\left(-\dfrac{7}{23}\right).\left(\dfrac{25}{28}\right)$$=\left(-\dfrac{7}{23}\right).\left(\dfrac{13}{28}+\dfrac{25}{28}\right)$$=\left(-\dfrac{7}{23}\right).\left(\dfrac{38}{28}\right)$$=\left(-\dfrac{7}{23}\right).\left(\dfrac{19}{14}\right)$$=-\dfrac{19}{46}$Câu trả lời: $\left(-\dfrac{7}{23}\right).\left(\dfrac{13}{28}\right)+\left(-\dfrac{7}{23}\right).\left(\dfrac{25}{28}\right)$$=\left(-\dfrac{7}{23}\right).\left(\dfrac{13}{28}+\dfrac{25}{28}\right)$$=\left(-\dfrac{7}{23}\right).\left(\dfrac{38}{28}\right)$$=\left(-\dfrac{7}{23}\right).\left(\dfrac{19}{14}\right)$$=-\dfrac{19}{46}$

Phước Lộc · Answer

$\left(-\dfrac{7}{23}\right)\cdot\left(\dfrac{13}{28}\right)+\left(-\dfrac{7}{13}\right)\cdot\left(\dfrac{25}{28}\right)$$=\left(-\dfrac{7}{23}\right)\cdot\left(\dfrac{13}{28}+\dfrac{25}{28}\right)$$=\left(-\dfrac{7}{13}\right)\cdot\dfrac{38}{28}$$=\left(-\dfrac{7}{13}\right)\cdot\dfrac{19}{14}$$=-\dfrac{19}{26}$Câu trả lời: $\left(-\dfrac{7}{23}\right)\cdot\left(\dfrac{13}{28}\right)+\left(-\dfrac{7}{13}\right)\cdot\left(\dfrac{25}{28}\right)$$=\left(-\dfrac{7}{23}\right)\cdot\left(\dfrac{13}{28}+\dfrac{25}{28}\right)$$=\left(-\dfrac{7}{13}\right)\cdot\dfrac{38}{28}$$=\left(-\dfrac{7}{13}\right)\cdot\dfrac{19}{14}$$=-\dfrac{19}{26}$

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