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\(-\dfrac{49}{81}.\dfrac{27}{-77}\)
\(=\dfrac{49.27}{81.77}\)
\(=\dfrac{7.7.27}{3.27.7.11}\)
\(=\dfrac{7}{3.11}\)
\(=\dfrac{7}{33}\)
12/49 > 13/47
64/85 > 73/81
19/31 > 17/35
67/77 > 73/83
\(A=\frac{9}{7}\times\frac{13}{5}\times\frac{9}{4}=\frac{1053}{140}\)
\(B=\frac{27}{5}\times\frac{13}{7}\times\frac{1}{4}=\frac{351}{140}\)
Vậy \(\frac{A}{B}=A:B=\frac{1053}{140}:\frac{351}{140}=\frac{1053}{351}=3\)
a) \(2.4.16.8=2.2^2.2^4.2^3=2^{1+2+4+3}=2^{10}\)
b) \(3^3.22^5.45=3^3.22^5.5.3^2=3^{3+2}.22^5=3^5.22^5=\left(3.22\right)^5=66^5\)
c) \(9.27.81=3^2.3^3.3^4=3^{2+3+4}=3^9\)
d) \(36.30.125=6^2.5.6.5^3=6^{2+1}.5^{3+1}=6^3.5^4\)
e) \(2.4.8.16.256=2.2^2.2^3.2^4.2^8=2^{1+2+3+4+8}=2^{18}\)
g) \(3.9.27.81.729=3.3^2.3^3.3^4.3^6=3^{1+2+3+4+6}=3^{16}\)
h) \(5.25.125.625.75=5.5^2.5^3.5^4.5^2.3=5^{1+2+3+4+2}.3=5^{12}.3\)
k) \(7.49.343.77=7.7^2.7^3.7.11=7^{1+2+3+1}.11=7^7.11\)
a) \(27^{64}:81^{20}=3^{192}:3^{80}=3^{112}\)
b) \(\left(\dfrac{1}{8}\right)^{20}:\left(\dfrac{1}{16}\right)^9=\left(\dfrac{1}{2}\right)^{60}:\left(\dfrac{1}{2}\right)^{36}=\left(\dfrac{1}{2}\right)^{24}\)
c) \(\dfrac{1}{3}:\dfrac{1}{5}-\dfrac{1}{6}=\dfrac{5}{3}-\dfrac{1}{6}=\dfrac{10}{6}-\dfrac{1}{6}=\dfrac{9}{6}=\dfrac{3}{2}\)
\(\dfrac{-49}{81}.\dfrac{27}{-27}=\dfrac{49}{81}\)
-49/81x27/(-77)
=-49x27/81x(-77)
=-1323/-6273
=1323/6273
=147/697