DN
1
K
Khách
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5 tháng 6 2019
a) \(\left|x+\frac{3}{5}\right|-\frac{1}{2}=\frac{1}{2}\)
\(\left|x+\frac{3}{5}\right|=\frac{1}{2}+\frac{1}{2}\)
\(\left|x+\frac{3}{5}\right|=1\)
\(=>x+\frac{3}{5}=1\) hoặc \(x+\frac{3}{5}=-1\)
=> x = \(1-\frac{3}{5}\) x = \(-1-\frac{3}{5}\)
x = \(\frac{2}{5}\) x = \(\frac{-8}{5}\)
b) -c) - d) làm tương tự
11 tháng 4 2019
\((2,7.x-1\frac{1}{2})\div\frac{2}{7}=\frac{-21}{4}\) \(3\frac{1}{3}.x+16\frac{3}{4}=-13.25\)
\(2,7.x-1\frac{1}{2}=-\frac{21}{4}\cdot\frac{2}{7}\) \(\frac{10}{3}.x+\frac{67}{4}=-13.25\)
\(2,7.x-\frac{3}{2}=-\frac{3}{2}\) \(\frac{10}{3}.x+\frac{67}{4}=-\frac{53}{4}\)
\(2,7.x=-\frac{3}{2}+\frac{3}{2}\) \(\frac{10}{3}.x=-\frac{53}{4}-\frac{67}{4}\)
\(2,7.x=0\) \(\frac{10}{3}.x=-30\)
\(x=0:2,7\) \(x=-30:\frac{10}{3}\)
\(x=0\) \(x=-9\)
Vậy x=0 Vậy x= -9
\(\left(4.5-2.x\right):\frac{3}{4}=1\frac{1}{3}\) \(1.5+1\frac{1}{4}.x=\frac{2}{3}\)
\(\left(4.5-2.x\right)=1\frac{1}{3}\cdot\frac{3}{4}\) \(1\frac{1}{4}.x=\frac{2}{3}-1.5\)
\(4.5-2.x=\frac{4}{3}\cdot\frac{3}{4}\) \(\frac{5}{4}.x=\frac{2}{3}-\frac{3}{2}\)
\(4.5-2.x=1\) \(\frac{5}{4}.x=-\frac{5}{6}\)
\(2.x=4.5-1\) \(x=-\frac{5}{6}:\frac{5}{4}\)
\(2.x=3.5\) \(x=-\frac{2}{3}\)
\(x=3.5:2\)
\(x=1.75\) Vậy \(x=-\frac{2}{3}\)
Vậy x=1.75
TN
2
8 tháng 8 2019
\(\left(x+\frac{3}{5}\right)^2+1\frac{16}{25}=9\%:4,5\%\)
\(\left(x+\frac{3}{5}\right)^2+1\frac{16}{25}=2\)
\(\left(x+\frac{3}{5}\right)^2=2-1\frac{16}{25}\)
\(\left(x+\frac{3}{5}\right)^2=\frac{9}{25}=\frac{3}{5}^2\)
\(x+\frac{3}{5}=\frac{3}{5}\)
\(x=\frac{3}{5}-\frac{3}{5}\)
\(x=0\)
8 tháng 8 2019
\(\left(x+\frac{3}{5}\right)^2+1\frac{16}{25}=9\%:4,5\%\)
\(\left(x+\frac{3}{5}\right)^2+1\frac{16}{25}=2\)
\(\left(x+\frac{3}{5}\right)^2=2-1\frac{16}{25}\)
\(\left(x-\frac{3}{5}\right)^2=\frac{3^2}{5}\)
\(x=\frac{3}{5}-\frac{3}{5}\)
\(x=0\)
KN
23 tháng 4 2019
\(\left(4,5+2x\right)\div\frac{3}{4}=-1\frac{1}{3}\)
\(\Leftrightarrow\left(4,5+2x\right)\div\frac{3}{4}=-\frac{4}{3}\)
\(\Leftrightarrow4,5+2x=-\frac{4}{3}\times\frac{3}{4}\)
\(\Leftrightarrow4,5+2x=-1\)
\(\Leftrightarrow2x=-1-4,5\)
\(\Leftrightarrow2x=-5,5\)
\(\Leftrightarrow x=-5,5\div2\)
\(\Leftrightarrow x=-2,75\)
10 tháng 5 2016
c)\(\frac{1}{2}x+\frac{1}{8}x=\frac{3}{4}\)
\(\Rightarrow x.\left(\frac{1}{2}-\frac{1}{8}\right)=\frac{3}{4}\)
\(\Rightarrow x.\frac{3}{8}=\frac{3}{4}\)
=>x\(=\frac{3}{4}:\frac{3}{8}\)
=>x=\(2\)
10 tháng 5 2016
a)\(x+\frac{1}{6}=\frac{-3}{8}\)
=>\(x=\frac{-3}{8}-\frac{1}{6}\)
=>\(x=\frac{-9}{24}-\frac{4}{24}\)
=>\(x=\frac{-13}{24}\)
b)\(2-\left|\frac{3}{4}-x\right|=\frac{7}{12}\)
=>\(\left|\frac{3}{4}-x\right|=2-\frac{7}{12}\)
=>\(\left|\frac{3}{4}-x\right|=\frac{24}{12}-\frac{7}{12}\)
\(\Rightarrow\left|\frac{3}{4}-x\right|=\frac{17}{12}\)
TH1: \(\frac{3}{4}-x=\frac{17}{12}\)
=>x=\(\frac{3}{4}-\frac{17}{12}\)
=>x=\(x=-\frac{2}{3}\)
TH2:\(\frac{3}{4}-x=-\frac{17}{12}\)
=>\(x=\frac{3}{4}-\left(-\frac{17}{12}\right)\)
=>x=\(x=\frac{13}{6}\)
Dzồi nhìu phết
\(3^2.x+2^3-4,5+3\frac{1}{2}x=16x+2^3-4,5-15x+6,2.\)
\(\Leftrightarrow9x+8-4,5+\frac{7}{2}x=16x+8-4,5-15x+6,2\)
\(\Leftrightarrow9x+\frac{7}{2}x-16x+15x=8-4,5+6,2-8+4,5\)
\(\Leftrightarrow11,5x=6,2\)
\(\Leftrightarrow x=\frac{62}{115}\)