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23 tháng 4 2019

\(\left(4,5+2x\right)\div\frac{3}{4}=-1\frac{1}{3}\)

\(\Leftrightarrow\left(4,5+2x\right)\div\frac{3}{4}=-\frac{4}{3}\)

\(\Leftrightarrow4,5+2x=-\frac{4}{3}\times\frac{3}{4}\)

\(\Leftrightarrow4,5+2x=-1\)

\(\Leftrightarrow2x=-1-4,5\)
\(\Leftrightarrow2x=-5,5\)

\(\Leftrightarrow x=-5,5\div2\)

\(\Leftrightarrow x=-2,75\)

a) Ta có: \(\frac{4}{5}+x=\frac{2}{3}\)

hay \(x=\frac{2}{3}-\frac{4}{5}=\frac{10}{15}-\frac{12}{15}=\frac{-2}{15}\)

Vậy: \(x=\frac{-2}{15}\)

b) Ta có: \(\frac{3}{4}-x=\frac{1}{3}\)

hay \(x=\frac{3}{4}-\frac{1}{3}=\frac{9}{12}-\frac{4}{12}=\frac{5}{12}\)

Vậy: \(x=\frac{5}{12}\)

c) Ta có: \(x-\frac{5}{9}=\frac{-2}{3}\)

hay \(x=\frac{-2}{3}+\frac{5}{9}=\frac{-6}{9}+\frac{5}{9}=-\frac{1}{9}\)

Vậy: \(x=\frac{-1}{9}\)

d) Ta có: \(\frac{\left(4,5-2x\right)}{\frac{3}{4}}=1\frac{1}{3}\)

\(\Leftrightarrow\frac{9}{2}-2x=\frac{4}{3}\cdot\frac{3}{4}=1\)

\(\Leftrightarrow2x=\frac{9}{2}-1=\frac{7}{2}\)

hay \(x=\frac{7}{4}\)

Vậy: \(x=\frac{7}{4}\)

28 tháng 4 2021

i don't know

21 tháng 4 2016

a, 2x+ 1/4 = 3/2

2x = 3/2-1/4

2x = 5/4

x=5/4:2

x= 5/8 

b, (x-5) - 1/3 = 2/5

x-5= 2/5+1/3

x-5=11/15

x=11/15+5

x=86/15

c, (4,5-2x):3/4=4/3

(4,5-2x)=4/3. 3/4

4,5-2x=1

2x= 5,5

x=5,5:2

x=2,75

21 tháng 4 2016

a) 2x+1/4=3/2

=> 2x      =3/2-1/4

=> 2x       =5/4

=> x         =5/4:2

=> x         =5/8

b) (x-5)-1/3=2/5

=>  x-5      =2/5+1/3

=> x-5        =11/15

=> x           =11/15+5

=> x           =86/15

c) (4,5-2x):3/4=4/3

=> 4,5-2x       =4/3x3/4

=> 4,5-2x       =1

=>   2x          =4,5-1

=>   2x           =3,5

=>    x             =3,5:2

=>    x             =1,75

a) \(3\frac{1}{3}\left(3\frac{1}{4}+2x\right)=6\frac{2}{3}\)

   \(3\frac{1}{3}\times3\frac{1}{4}+2x=6\frac{2}{3}\)

   \(10\frac{5}{6}+2x=6\frac{2}{3}\)

   \(2\times x=6\frac{2}{3}+10\frac{5}{6}=17,5\)

   \(x=17,5\div2=8,75\)

Vậy x = 8,75

b) \(x-25\%x=\frac{6}{11}\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\)

   \(x-\frac{25}{100}x=\frac{6}{11}\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\)

   \(x-\frac{1}{4}\times x=\frac{6}{11}\times1\frac{7}{12}=\frac{19}{22}\)

   \(x\times x=\frac{19}{22}+\frac{1}{4}=\frac{49}{44}\)

\(\Rightarrow2x\left(x\times x\right)=\frac{49}{44}\)   

   \(x=\frac{49}{44}\div2=\frac{49}{88}\)

   Vậy x = \(\frac{49}{88}\)

c) \(\left(4,5-2x\right)\times1\frac{4}{7}=\frac{11}{14}\)

   \(4,5-2x\times1\frac{4}{7}=\frac{11}{14}\)

   \(-2x\times1\frac{4}{7}=\frac{11}{14}-4,5=-3\frac{5}{7}\)

   \(-2\times x=-3\frac{5}{7}\div1\frac{4}{7}=-2\frac{4}{11}\)

   \(x=-2\frac{4}{11}\div\left(-2\right)=1\frac{2}{11}\)

Vậy x = \(1\frac{2}{11}\)

d) \(-3^2-|2x+3|=4\)

    \(9-|2x+3|=4\)

   \(-|2x+3|=4-9=-5\)

   \(-|2x|=-5-|3|=-8\)

   \(-|x|=-8\div2=-4\)

    \(-x=4\Rightarrow x=-4\)

   Vậy x = -4 (-x được xem là số đối của x)

15 tháng 4 2021

a, \(\dfrac{3}{15}-x=-\dfrac{1}{7}\Leftrightarrow\dfrac{21-105x}{105}=\dfrac{-15}{105}\Rightarrow-105x=-36\)

\(\Leftrightarrow x=\dfrac{36}{105}=\dfrac{12}{35}\)

b, \(\left(4,5+\dfrac{3}{4}x\right):\dfrac{8}{3}=\dfrac{9}{3}\Leftrightarrow\dfrac{45}{10}+\dfrac{3x}{4}=\dfrac{72}{9}=8\)

\(\Leftrightarrow\dfrac{36}{4}+\dfrac{3x}{4}=\dfrac{32}{4}\Rightarrow3x=-4\Leftrightarrow x=-\dfrac{4}{3}\)

c, mình ko hiểu đề lắm 

28 tháng 10 2017

\(\left(\frac{1}{4}x-1\right)+\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+1\right)=4,5\)

\(\frac{1}{4}x-1+\frac{5}{6}x-2-\frac{3}{8}x-1=\frac{9}{2}\)

\(\left(\frac{1}{4}x+\frac{5}{6}x-\frac{3}{8}x\right)=\frac{9}{2}+1+2+1\)

\(\frac{17}{24}x=\frac{17}{2}\)

\(x=\frac{17}{2}:\frac{17}{24}\)

\(x=\frac{17}{2}.\frac{24}{17}\)

\(x=\frac{24}{2}\)

\(x=12\)

vậy \(x=12\)

5 tháng 5 2023

`(2x-4,5):3/4-1/3=1`

`=>(2x-4,5):3/4=1+1/3`

`=>(2x-4,5):3/4=3/3+1/3`

`=>(2x-4,5):3/4=4/3`

`=>2x-4,5=4/3xx3/4`

`=>2x-4,5=1`

`=>2x=1+4,5`

`=>2x=5,5`

`=>x=2,75`

8 tháng 5 2023

=>(2�−4,5):3/4=1+1/3

=>(2�−4,5):3/4=3/3+1/3

=>(2�−4,5):3/4=4/3

=>2�−4,5=4/3��3/4

=>2�−4,5=1

=>2�=1+4,5

=>2�=5,5

=>�=2,75

=>(2x-9/2):3/4=4/3

=>(2x-9/2)=1

=>2x=11/2

=>x=11/4

24 tháng 1 2023

\(\left(2x-4,5\right):\dfrac{3}{4}-\dfrac{1}{3}=1\)

\(\left(2x-4,5\right):\dfrac{3}{4}=1+\dfrac{1}{3}\)

\(\left(2x-4,5\right):\dfrac{3}{4}=\dfrac{4}{3}\)

\(2x-4,5=\dfrac{4}{3}\times\dfrac{3}{4}\)

\(2x-4,5=1\)

\(2x=1+4,5\)

\(2x=5,5\)

\(x=5,5:2\)

\(x=2,75\)