x*3+x*10+x*21+36*x+x*30= 190
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3-(17-x)=289-(36+289)
<=> 3-17+x=289-36-289
<=> -14+x=-36 => x=-22
25-(x+5)=-45-(15-45)
<=> 25-x-5=-45-15+45
<=> 20-x=-15=> x=35
34-(21-x)=(3747-30)-3747
<=> 334-21+x=3747-30-3747
<=> 313+x=-30=> x=-343
3 - ( 17 - x ) = 289 - ( 36 + 289 )
3 - 17 + x = 289 - 36 - 289
- 14 + x = - 36
x = ( - 36 ) - ( - 14 )
x= - 22
25 - ( x + 5 ) = - 45 - ( 15 - 45)
25 - x - 5 = - 45 - 15 + 45
20 - x = - 15
x = 20 - ( - 15 )
x = 35
34 - ( 21 - x ) = ( 3747 - 30 ) - 3747
34 - 21 + x = 3747 - 30 - 3747
13 + x = - 30
x = ( - 30 ) - 13
x = - 46
a)-Ix-3I+16=4
-Ix-3I=4-16
-Ix-3I=-12
-IxI=-12+3
-IxI=-9
x=-9
b)3-(17-x)=289-(36+289)
3-(17-x)=289-325
3-(17-x)=-36
(17-x)=3-(-36)
(17-x)=39
x=17-39
x=-22
c)25-(x+5)=415-(15-415)
25-(x+5)=415-(-400)
25-(x+5)=815
(x+5)=25-815
(x+5)=-790
x=(-790)-5
x=-795
d)34+(21-x)=(3747-30)-3746
34+(21-x)=3717-3746
34+(21-x)=-29
31+x=21-(-29)
31+x=50
x=50-31
x=19
a, \(\frac{2}{x}=\frac{y}{4}\Leftrightarrow xy=8\)
Suy ra : \(x;y\inƯ\left(8\right)=\left\{1;2;4;8\right\}\)tự lập bảng
b, Xét : \(\frac{1}{x}=\frac{5}{15}\Leftrightarrow\frac{5}{5x}=\frac{5}{15}\Leftrightarrow x=3\)
\(\frac{y}{21}=\frac{5}{15}\Leftrightarrow15y=105\Leftrightarrow y=3\)
\(\frac{10}{z}=\frac{5}{15}\Leftrightarrow5z=150\Leftrightarrow z=30\)
c, tương tự b
\(\frac{x}{6}+\frac{x}{10}+\frac{x}{15}+\frac{x}{21}+\frac{x}{28}+\frac{x}{36}=\frac{8}{9}\)
\(\Leftrightarrow\frac{x}{12}+\frac{x}{20}+\frac{x}{30}+\frac{x}{42}+\frac{x}{56}+\frac{x}{72}=\frac{8}{18}=\frac{4}{9}\)
\(\Leftrightarrow\frac{x}{3.4}+\frac{x}{4.5}+\frac{x}{5.6}+\frac{x}{6.7}+\frac{x}{7.8}+\frac{x}{8.9}=\frac{4}{9}\)
\(\Leftrightarrow\frac{x}{3}-\frac{x}{4}+\frac{x}{4}-\frac{x}{5}+\frac{x}{5}-\frac{x}{6}+...+\frac{x}{8}-\frac{x}{9}=\frac{4}{9}\)
\(\Leftrightarrow\frac{x}{3}-\frac{x}{9}=\frac{4}{9}\Leftrightarrow\frac{2x}{9}=\frac{4}{9}\Leftrightarrow x=2\)
x * 3 +x * 10 + x * 21 + 36 * x + x * 30 = 190
x * ( 3 + 10 + 21 + 36 + 30 ) = 190
x * 100 = 190
x = 190 : 100
x = 1,9
1,9 là đáp án chuẩn xác nhất