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3 x 15 + 21 x 15 + 85 x 5
= 45 + 315 + 425
= 785
15 - 30 + 40
= 25
21 + 19 - 50 + 10
= 0
\(\dfrac{1}{5}-\dfrac{1}{4}+2\)
\(=-\dfrac{1}{20}+2\)
\(=\dfrac{39}{20}\)
\(\left(\dfrac{1}{4}+\dfrac{1}{6}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\)
\(=\dfrac{5}{12}\times\dfrac{1}{4}\)
\(=\dfrac{5}{12}\times\dfrac{3}{12}\)
\(=\dfrac{5}{48}\)
\(\dfrac{1}{10}+\dfrac{1}{5}-\dfrac{3}{4}\)
\(=-\dfrac{9}{20}\)
\(3\times15+21\times15+85\times5\\ =15\times\left(3+21\right)+425\\ =15\times24+425\\ =360+425\\ =785\)
\(15-30+40\\ =\left(15+40\right)-30\\ =55-30\\ =25\)
\(21+19-50+10\\ =\left(21+19\right)-\left(50-10\right)\\ =40-40\\ =0\)
\(\dfrac{1}{5}-\dfrac{1}{4}+2\)
\(=\dfrac{4}{20}-\dfrac{5}{20}+\dfrac{40}{20}\)
\(=\dfrac{\left(4+40\right)}{20}-\dfrac{5}{20}\)
\(=\dfrac{44}{20}-\dfrac{5}{20}\)
\(=\dfrac{39}{20}\)
\(\left(\dfrac{1}{4}+\dfrac{1}{6}\right)\times\left(\dfrac{1}{2}-\dfrac{1}{4}\right)\)
\(=\dfrac{5}{12}\times\dfrac{1}{4}\)
\(=\dfrac{5}{48}\)
\(\dfrac{1}{10}+\dfrac{1}{5}-\dfrac{3}{4}\)
\(=\dfrac{2}{20}+\dfrac{4}{20}-\dfrac{15}{20}\)
\(=\dfrac{6}{20}-\dfrac{15}{20}\)
\(=-\dfrac{9}{20}\)
a, 3x X +122=21
\(3xX=21-122\)
\(3xX=-101\)
\(X=-101:3\)
\(X=-\frac{101}{3}\)
b,(36-X):2=10
\(36-X=10x2\)
\(36-X=20\)
\(X=36-20\)
\(X=16\)
c, 36-X:2 = 10
\(36-X:2=10\)
\(X:2=36-10\)
\(X:2=26\)
\(X=26x2\)
\(X=52\)
a.3xX+122=21
3xX =21-122
3xX =-101
X =-101:3
X =\(\frac{-101}{3}\)
A) 4,29 x 1230 - 429 x 2,3
= 429 x 12,3 - 429 x 2,3
= 429 x ( 12,3 - 2,3 )
= 429 x 10
= 4290
B) 30 - 15 + 36 - 18 + 42 - 21 + ... + 96 - 48 + 102 - 51
= ( 15 + 15 ) - 15 + ( 18 + 18 ) - 18 + ... + ( 48 + 48 ) - 48 + ( 51 + 51 ) - 51
= 15 + 18 + 21 + ... + 48 + 51
= [( 51 - 15 ) : 3 + 1] x ( 15 + 51 ) : 2
= [36 : 3 + 1] x 66 : 2
= [12 + 1] x 33
= 13 x 33
= 429
a) y + 25,6 = 76,5 : 1,8
y + 25,6 = 42,5
y = 42,5 - 25,6
y = 16,9
b) y - 2,46 = 9,1 : 3,5
y - 2,46 = 2,6
y = 2,6 + 2,46
y = 5,06
c) y x 0,6 = 1,8 x 10
y x 0,6 = 18
y = 18 : 0,6
y = 30
d) 190 : x = 22,96 - 15,36
190 : x = 7,6
x = 190 : 7,6
x = 25
\(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+....+\frac{1}{x.\left(x+2\right)}=\frac{20}{41}\)
\(\Rightarrow\frac{1}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{x.\left(x+2\right)}\right)=\frac{20}{41}\)
\(\Rightarrow\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+....+\frac{1}{x}-\frac{1}{x+2}\right)=\frac{20}{41}\)
\(\Rightarrow\frac{1}{2}.\left(1-\frac{1}{x+2}\right)=\frac{20}{41}\)
\(\Rightarrow1-\frac{1}{x+2}=\frac{20}{41}:\frac{1}{2}\)
\(\Rightarrow1-\frac{1}{x+2}=\frac{40}{41}\)
\(\Rightarrow\frac{1}{x+2}=1-\frac{40}{41}=\frac{1}{41}\)
=> x + 2 = 41
=> x = 39
x * 3 +x * 10 + x * 21 + 36 * x + x * 30 = 190
x * ( 3 + 10 + 21 + 36 + 30 ) = 190
x * 100 = 190
x = 190 : 100
x = 1,9
1,9 là đáp án chuẩn xác nhất