25+`15 >Y-6>66-28
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x.(\(\dfrac{1}{6}\)+\(\dfrac{1}{10}\)+\(\dfrac{1}{15}\)+\(\dfrac{1}{21}\)+\(\dfrac{1}{28}\)+\(\dfrac{1}{36}\)+\(\dfrac{1}{45}\)+\(\dfrac{1}{55}\)+\(\dfrac{1}{66}\)+\(\dfrac{1}{78}\))=\(\dfrac{220}{39}\)
x.\(\dfrac{20}{39}\)=\(\dfrac{220}{39}\)
x=\(\dfrac{220}{39}\):\(\dfrac{20}{39}\)
x=11
Bài làm:
Ta có: \(1+\frac{1}{3}+\frac{1}{6}+...+\frac{1}{66}\)
\(=\frac{1}{1}+\frac{1}{1.3}+\frac{1}{3.2}+...+\frac{1}{11.6}\)
\(=\frac{1}{2}\left(\frac{1}{1.2}+\frac{1}{2.1.3}+\frac{1}{2.3.2}+...+\frac{1}{2.11.6}\right)\)
\(=\frac{1}{2}\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{11.12}\right)\)
\(=\frac{1}{2}\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{11}-\frac{1}{12}\right)\)
\(=\frac{1}{2}\left(1-\frac{1}{12}\right)\)
\(=\frac{1}{2}.\frac{11}{12}\)
\(=\frac{11}{24}\)
\(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+\frac{1}{21}+\frac{1}{28}+\frac{1}{36}+\frac{1}{45}+\frac{1}{55}+\frac{1}{66}\)
\(=\frac{2}{2}+\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+...+\frac{2}{90}+\frac{2}{110}+\frac{2}{132}\)
\(=2\times\left(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}+...+\frac{1}{9\times10}+\frac{1}{10\times11}+\frac{1}{11\times12}\right)\)
\(=2\times\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}\right)\)
\(=2\times\left(1-\frac{1}{12}\right)\)
\(=2\times\frac{11}{12}\)
\(=\frac{11}{6}\)
\(a,\frac{42}{25}:\frac{y}{5}=\frac{6}{5}\)
\(\frac{y}{5}=\frac{42}{25}:\frac{6}{5}\)
\(\frac{y}{5}=\frac{42}{25}\times\frac{5}{6}\)
\(\frac{y}{5}=\frac{7}{5}\)
\(\Leftrightarrow5y=7.5\)
\(5y=35\)
\(y=7\)
x.(1/6+1/10+1/15+1/21+1/28+1/36+1/45+1/55+1/66+1/78)=220/39
x.20/39=220/39
x=220/39:20/39
x=11
25 + 15 > y - 6 > 66 - 28
40 > y - 6 > 38
Vậy 39 + 6 = 45
vậy y = 45
tk nha
thanks@@@@@@@@
40>y-6>38
suy ra y-6=39
y =39+6
y = 45