Question

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Answer 1

[๖ۣۜHả๖ۣۜI]

c. \(\dfrac{5x+4}{3}-1=\dfrac{3x-2}{4}\\ \Leftrightarrow\dfrac{4\left(5x+4\right)}{12}-\dfrac{12}{12}=\dfrac{3\left(3x-2\right)}{12}\\ \Leftrightarrow20x+16-12=9x-6\\ \Leftrightarrow20x-9x=-6+12-16\\ \Leftrightarrow11x=-10\\ \Leftrightarrow x=-\dfrac{10}{11}\)

d. \(\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=\dfrac{4x}{x^2-1}\\ ĐKXĐ:x\ne1;x\ne-1\\ \Leftrightarrow\dfrac{\left(x+1\right)\left(x+1\right)}{x^2-1}-\dfrac{\left(x-1\right)\left(x-1\right)}{x^2-1}=\dfrac{4x}{x^2-1}\\ \Leftrightarrow x^2+1-x^2+1=4x\\ \Leftrightarrow4x=0\\ \Leftrightarrow x=0\left(n.h.ậ.n\right)\)