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12 tháng 12 2021

1. what he often did on Sunday mornings.

2. I must finish the report by ten o'clock

3. was hot so we turned on the air conditional

4. my favourite band wouldn't leave here tomorrow

5. have you learned English?

6. Tung if he liked dancing.

7. so she got good grades in her exam

8.  he didn't make such terrible mistakes

9. Tom what  he would do after that class.

18 tháng 3 2022

ảnh lỗi

Câu 3: 

a: \(BD=\sqrt{BC^2-DC^2}=4\left(cm\right)\)

b: \(\widehat{A}=180^0-2\cdot70^0=40^0< \widehat{B}\)

nên BC<AC=AB

c: Xét ΔEBC vuông tại E và ΔDCB vuông tại D có

BC chung

\(\widehat{EBC}=\widehat{DCB}\)

Do đó:ΔEBC=ΔDCB

d: Xét ΔOBC có \(\widehat{OBC}=\widehat{OCB}\)

nên ΔOBC cân tại O

Bài 4: 

\(x=130^0\)

4 tháng 12 2021

cụ thể hơn đc ko ạ

27 tháng 11 2021

1 were - would you play

2 weren't studying - would have 

3 had taken - wouldn't have got

4 would you go - could

5 will you give - is

6 recycle - won't be

7 had heard - wouldn't have gone

8 would you buy - had

9 don't hurry - will miss

10 had phoned - would have given

11 were - wouldn't eat

12 will go - rains

13 had known - would have sent

14 won't feel - swims

15 hadn't freezed - would have gone

26 tháng 12 2022

\(a,=\dfrac{x^3+2x}{\left(x-1\right)\left(x^2+x+1\right)}+\dfrac{2}{x^2+x+1}-\dfrac{1}{x-1}=\dfrac{x^3+2x+2x-2-\left(x^2+x+1\right)}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{x^3+3x-3}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{x^3+3}{\left(x^2+x+1\right)}\)

26 tháng 12 2022

cho mik câu trả lời chii tiết nhất với ạ !!

 

14 tháng 10 2021

em chịuem thua

14 tháng 10 2021

cái gì đây?

2 A

3 D

4 A

5 A

6 B

7 A

8 A

9 A

a: \(=\dfrac{x^3+2x+2x-2-x^2-x-1}{\left(x-1\right)\left(x^2+x+1\right)}\)

\(=\dfrac{x^3-x^2+3x-3}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{x^2+3}{x^2+x+1}\)

b: \(=\dfrac{x^2-2x-3+x^2+2x-3+2x-2x^2}{\left(x-3\right)\left(x+3\right)}\)

\(=\dfrac{2x-6}{\left(x-3\right)\left(x+3\right)}=\dfrac{2}{x+3}\)

c: \(=\dfrac{6-7+x}{3\left(x-1\right)}=\dfrac{x-1}{3\left(x-1\right)}=\dfrac{1}{3}\)

d: \(=\dfrac{x^3+2x+2x-2-x^2-x-1}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{x^3-x^2+3x-3}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{x^2+3}{x^2+x+1}\)

17 tháng 9 2021

1 is explained

2 was stolen

3 will be opened

4 is being closed

5 is going to be built

17 tháng 9 2021

Cảm ơn bạn ạ

16 tháng 3 2022

1C

2A

3C

4B

5C

6D

7B

8A

9D

10C