giúp mik nhá cần gấp ạ
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2. grandparents
3. single
4. single
5. daughter
6. surname
My name is Nhan, i'm 12. My hoppy is listen to music, draw and watch TV. On holiday, I spend most of my time to perform hobbies. I spend most of my time watching TV, then listening to music and drawing a bit. My friends are very few watching TV, they often hang out, meet friends and exercise.I did not go out much, so I watched TV as direct contact with nature outside. In addition to watching TV, my second preference is listening to music. I hear their melody and enjoy it, and it makes me feel more relaxed and relaxed.Finally drawing, I loved drawing since childhood and my dream is to become a painter. I love these hobbies.
nè bạnMy favourite hobby is reading. I enjoy reading a book when I am free. I started to do it when I was four years old. The first time I did it, I felt interested. So I kept reading. The teachers always taught me to read the difficult words. I was happy when I read a story with a happy ending. I was thrilled when I read a detective story. I enjoy reading because I like to explore the imaginative world of my favourite author, J.K.Rowling who writes “ Harry Potter” . There are a lot of advantages of reading. Reading can make me relaxed and calm. I can also learn new vocabulary items. Then I can further improve my English. Moreover, it can give me an unlimited imagination, so I can write books in the future. I can learn the different cultures and customs of other countries in the world too. I read at least one hour every day. I read books by myself. I usually read it at home. I wish I could read different kinds of books because it might be very challenging.
tham khảo nha bạn!
ummm....mình nghĩ bn có thể tham khảo cái câu này=,)
I do my homework trong đó có:
I: S
do: V
my homework: O
hoặc là Peter is reading a novel
Peter: S
is reading: V
a novel: O
:DD
29: Ta có: \(\dfrac{1}{\sqrt{7}+\sqrt{5}}+\dfrac{2}{1-\sqrt{7}}\)
\(=\dfrac{\sqrt{7}-\sqrt{5}}{2}-\dfrac{2\sqrt{7}-2}{6}\)
\(=\dfrac{3\sqrt{7}-3\sqrt{5}-2\sqrt{7}+2}{6}\)
\(=\dfrac{-3\sqrt{5}-2}{6}\)
30: Ta có: \(\dfrac{4}{1-\sqrt{3}}+\dfrac{\sqrt{3}-1}{\sqrt{3}+1}\)
\(=\dfrac{-4\sqrt{3}-4}{2}+\dfrac{4-2\sqrt{3}}{2}\)
\(=\dfrac{-4\sqrt{3}-4+4-2\sqrt{3}}{2}=-3\sqrt{3}\)
31: Ta có: \(\dfrac{1}{\sqrt{2}-\sqrt{3}}-\dfrac{3}{\sqrt{18}+2\sqrt{3}}\)
\(=-\sqrt{3}-\sqrt{2}-\dfrac{3}{3\sqrt{2}+2\sqrt{3}}\)
\(=-\sqrt{3}-\sqrt{2}-\dfrac{9\sqrt{2}-6\sqrt{3}}{6}\)
\(=\dfrac{-6\sqrt{3}-6\sqrt{2}-9\sqrt{2}+6\sqrt{3}}{6}=\dfrac{-15\sqrt{2}}{6}\)
\(=\dfrac{-5\sqrt{2}}{2}\)
29.
\(=\frac{\sqrt{7}-\sqrt{5}}{(\sqrt{7}-\sqrt{5})(\sqrt{7}+\sqrt{5})}+\frac{2(1+\sqrt{7})}{(1-\sqrt{7})(1+\sqrt{7})}\)
\(=\frac{\sqrt{7}-\sqrt{5}}{7-5}+\frac{2(1+\sqrt{7})}{1-7}=\frac{\sqrt{7}-\sqrt{5}}{2}-\frac{1+\sqrt{7}}{3}=\frac{\sqrt{7}-3\sqrt{5}-2}{6}\)