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Bài 1:
a. \(R=p\dfrac{l}{S}=1,10.10^{-6}\dfrac{30}{0,3\cdot10^{-6}}=110\Omega\)
b. \(I=U:R=220:110=2A\)
Bài 2:
a. \(R=R1+R2=30+50=80\Omega\)
b. \(I=I1=I2=0,25A\left(R1ntR2\right)\)
\(\left\{{}\begin{matrix}U1=I1\cdot R1=0,25\cdot30=7,5V\\U2=I2\cdot R2=0,25\cdot50=12,5V\\U=IR=0,25\cdot80=20V\end{matrix}\right.\)
Câu 1.
a)\(R=\rho\cdot\dfrac{l}{S}=1,1\cdot10^{-6}\cdot\dfrac{30}{0,3\cdot10^{-6}}=110\Omega\)
b)\(I=\dfrac{U}{R}=\dfrac{220}{110}=2A\)
Câu 2.
a)\(R_{AB}=R_1+R_2=30+50=80\Omega\)
b)\(I_1=I_2=I_A=0,25A\)
\(U_1=R_1\cdot I_1=30\cdot0,25=7,5V\)
\(U_2=R_2\cdot I_2=50\cdot0,25=12,5V\)
\(U_{AB}=U_1+U_2=7,5+12,5=20V\)
Câu 3.
a)\(R_{AB}=\dfrac{R_1\cdot R_2}{R_1+R_2}=\dfrac{600\cdot900}{600+900}=360\Omega\)
b)\(U_1=U_2=U_m=220V\)
\(I_1=\dfrac{U_1}{R_1}=\dfrac{220}{600}=\dfrac{11}{30}A\)
\(I_2=\dfrac{U_2}{R_2}=\dfrac{220}{900}=\dfrac{11}{45}A\)
\(I_m=I_1+I_2=\dfrac{11}{30}+\dfrac{11}{45}=\dfrac{11}{18}A\)
1. In spite of being a poor student, he studied very well
2. Despite the bad weather, she went to school on time
3. Despite having a physical handicap, she has become a successful woman
4. In spite of having not finished the paper, he went to sleep
5. Despite having a lot of noise in the city, I prefer living there
1. In spite of being a poor student, he studied very well
2. Despite the fact that the weather was bad, she went to school on time.
Diện tích 1 viên gạch là:
40x40=1600(cm2)
Diện tích căn phòng là:
1600x150=240000(m2)
Đổi 240000m2=24m2
Đáp số:24m2
Đổi : 40cm = 0,4m
Diện tích một viên gạch vuông là :
0,4 x 0,4 = 0,16 ( m2 )
Diện tích căn phòng là :
0,16 x 150 = 24 ( m2 )
Đáp số :......
1. Because of studying hard, I passed the exam
2. Because of Hoa's richness, she could buy that house
3. Because of bad grades, she failed the University entrance exam
4. Because of the accident, I was late
5. Because of the terrible traffic, we didn't arrive until 6 o'clock