tìm x: x+4/x-2=-3/4.mình cần gấp
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\(\left(x-2\right)\left(x^2+2x+4\right)-x\left(x-3\right)\left(x+3\right)=10\\ \Leftrightarrow x^3-8-x\left(x^2-9\right)=10\\ \Leftrightarrow x^3-8-x^3-9x=10\\ \Leftrightarrow-9x=18\\ \Leftrightarrow x=-2\)
\(a,50\%x-0,2+x=\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{1}{2}x-0,2+x=\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{1}{2}x+x=\dfrac{4}{5}+0,2\)
\(\Leftrightarrow\dfrac{3}{2}x=\dfrac{4}{5}+\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{3}{2}x=1\)
\(\Leftrightarrow x=\dfrac{2}{3}\)
\(b,\left(x-\dfrac{3}{4}\right):\dfrac{1}{2}+\dfrac{3}{2}=\dfrac{25}{2}\)
\(\Leftrightarrow\left(x-\dfrac{3}{4}\right).2=\dfrac{25}{2}-\dfrac{3}{2}\)
\(\Leftrightarrow\left(x-\dfrac{3}{4}\right).2=\dfrac{22}{2}\)
\(\Leftrightarrow x-\dfrac{3}{4}=11:2\)
\(\Leftrightarrow x=\dfrac{11}{2}+\dfrac{3}{4}\)
\(\Leftrightarrow x=\dfrac{25}{4}\)
Bài làm
X x 2 + X x 3 + X x 4 + X = 2130
X x ( 2 + 3 + 4 + 1 ) = 2130
X x 10 = 2130
X = 2130 : 10
X = 2130
Vậy X = 2130
# Học tốt #
\(\left(x-\frac{1}{3}\right)^3:\frac{2}{3}=-\frac{4}{9}\)
\(\Rightarrow\left(x-\frac{1}{3}\right)^3=-\frac{4}{9}.\frac{2}{3}\)
\(\Rightarrow\left(x-\frac{1}{3}\right)^3=-\frac{8}{27}\)
\(\Rightarrow x-\frac{1}{3}=-\frac{2}{3}\)
\(\Rightarrow x=-\frac{2}{3}+\frac{1}{3}\)
\(\Rightarrow x=-\frac{1}{3}\)
Vậy \(x=-\frac{1}{3}\)
Chúc bạn học tốt !!!
- Ta có: \(\frac{x+4}{x-2}=\frac{-3}{4}\)
\(\Rightarrow4.\left(x+4\right)=-3.\left(x-2\right)\)
\(\Leftrightarrow4x+16=-3x+6\)
\(\Leftrightarrow4x+3x=6-16\)
\(\Leftrightarrow7x=-10\)
\(\Leftrightarrow x=-\frac{10}{7}\)
Vậy \(S=\left\{-\frac{10}{7}\right\}\)
ok cám ơn bạn.