Mn giúp mk vs nhé
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a. Giả sử: \(3+\sqrt{12}>\sqrt{16}\)
<=> \(\sqrt{12}>1\) (thỏa mãn)
Vậy \(3+\sqrt{12}>\sqrt{16}\)
b. \(4\sqrt{7}=\sqrt{4^2.7}=\sqrt{112}\)
\(3\sqrt{13}=\sqrt{3^2.13}=\sqrt{117}\)
Ta thấy: 112 < 117
Vậy \(4\sqrt{7}< 3\sqrt{13}\)
My hobby is listening to music. I started this hobby 2 years ago, when I saw an interesting music show on TV and I liked it right away. After that, I shared my hobby with my brother, Phuc, and he liked it too. To continue my hobby, I always go to the concert, or listen to music in my free time. When I listen to music, I feel comfortable. Listening to music is very useful and helpful, so I will continue this hobby in the future.
\(a)P=\left(\dfrac{x^2+2}{x^3-1}+\dfrac{x+1}{x^2+x+1}+\dfrac{1}{1-x}\right).\left(\dfrac{x^2}{x+1}+1\right).\left(x\ne1;x\ne-1\right).\\ P=\dfrac{x^2+2+x^2-1-x^2-x-1}{\left(x-1\right)\left(x^2+x+1\right)}.\dfrac{x^2+x+1}{x+1}.\\ P=\dfrac{x^2-x}{x-1}.\dfrac{1}{x+1}.\\ P=\dfrac{x\left(x-1\right)}{x-1}.\dfrac{1}{x+1}.\\ P=x.\dfrac{1}{x+1}.\\ P=\dfrac{x}{x+1}.\)
\(P=\dfrac{1}{4}.\Rightarrow\dfrac{x}{x+1}=\dfrac{1}{4}.\\ \Leftrightarrow4x-x-1=0.\\ \Leftrightarrow3x-1=0.\\ \Leftrightarrow x=\dfrac{1}{3}\left(TM\right).\)
MN là đường trung bình đúng không hay chỉ đơn thuần là song song thôi
\(\left(2013.2014+2014.2015+2015.2016\right).\left(1+\frac{1}{3}-1-\frac{1}{3}\right)\)
\(=\left(2013.2014+2014.2015+2015.2016\right).0\)
= 0