So sánh:
\(M=\frac{-7}{10^{2011}}+\frac{-15}{10^{2012}}\) với \(N=\frac{-15}{10^{2011}}+\frac{-8}{10^{2012}}\)
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TM
8 tháng 3 2023
Ta có : \(M=-\dfrac{7}{10^{2011}}+\dfrac{-15}{10^{2012}}\) và \(N=\dfrac{-15}{10^{2011}}+\dfrac{-8}{10^{2012}}\)
Xét \(M=-\dfrac{7}{10^{2011}}-\dfrac{15}{10^{2012}}=-\dfrac{1}{10^{2011}}\left(7+\dfrac{15}{10}\right)=-\dfrac{1}{10^{2011}}\cdot\dfrac{17}{2}\).
Xét \(N=-\dfrac{15}{10^{2011}}-\dfrac{8}{10^{2012}}=-\dfrac{1}{10^{2011}}\left(15+\dfrac{8}{10}\right)=-\dfrac{1}{10^{2011}}\cdot\dfrac{79}{5}\).
Ta cũng có : \(\dfrac{M}{N}=\dfrac{-\dfrac{1}{10^{2011}}\cdot\dfrac{17}{2}}{-\dfrac{1}{10^{2011}}\cdot\dfrac{79}{5}}=\dfrac{\dfrac{17}{2}}{\dfrac{79}{5}}=\dfrac{85}{158}\)
\(\Rightarrow M=\dfrac{85}{158}N\). Mà \(\dfrac{85}{158}< 1\) nên \(M< N\).
Vậy : \(M< N\).
LD
0
DN
0
PH
0
N
0
12 tháng 1 2019
b,Ta có
\(\frac{2010}{2011}>\frac{2010}{2011+2012+2013}\)
\(\frac{2011}{2012}>\frac{2011}{2011+2012+2013}\)
\(\frac{2012}{2013}>\frac{2012}{2011+2012+2013}\)
\(\Rightarrow P>Q\)
12 tháng 1 2019
\(A=\frac{-10}{20}+\frac{-10}{30}+\frac{-10}{42}+\frac{-10}{56}+\frac{-10}{72}+\frac{-10}{90}+\frac{-10}{110}\)
\(=-10\left(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{110}\right)\)
\(=-10\left(\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+\frac{1}{10.11}\right)\)
\(=-10\left(\frac{1}{4}-\frac{1}{11}\right)\)
\(=\frac{-35}{22}\)
ML
5 tháng 7 2017
a) \(\frac{2^{10}+1}{2^{10}-1}\)và \(\frac{2^{10}-1}{2^{10}-3}\)
Ta có chính chất phân số trung gian là \(\frac{2^{10}+1}{2^{10}-3}\)
\(\frac{2^{10}+1}{2^{10}-1}>\frac{2^{10}+1}{2^{10}-3}\) ; \(\frac{2^{10}-1}{2^{10}-3}< \frac{2^{10}+1}{2^{10}-3}\)
Vì \(\frac{2^{10}+1}{2^{10}-1}>\frac{2^{10}+1}{2^{10}-3}>\frac{2^{10}-1}{2^{10}-3}\)
Nên \(\frac{2^{10}+1}{2^{10}-1}>\frac{2^{10}-1}{2^{10}-3}\)
b) \(A=\frac{2011}{2012}+\frac{2012}{2013}\)và \(B=\frac{2011+2012}{2012+2013}\)
Ta có : \(A=\frac{2011}{2012}+\frac{2012}{2013}>\frac{2011}{2013}+\frac{2012}{2013}=\frac{2011+2012}{2013}>\frac{2011+2012}{2012+2013}=B\)
Vậy A > B
Có gì sai cho sorry
5 tháng 7 2017
a,
\(\frac{2^{10}+1}{2^{10}-1}=1+\frac{2}{2^{10}-1}< 1+\frac{2}{2^{10}-3}=\frac{2^{10}-1}{2^{10}-3}\)
b,
\(\frac{2011}{2012}+\frac{2012}{2013}>\frac{2011}{2012+2013}+\frac{2012}{2012+2013}=\frac{2011+2012}{2012+2013}\)
I2
1
MN
21 tháng 3 2020
Có : \(A=\frac{10^{2012}-10}{10^{2013}-10}\)
\(\Leftrightarrow10A=\frac{10^{2013}-100}{10^{2013}-10}\)
\(\Leftrightarrow10A=\frac{10^{2013}-10-90}{10^{2013}-10}\)
\(\Leftrightarrow10A=1-\frac{90}{10^{2013}-10}\)
Có : \(B=\frac{10^{2011}+10}{10^{2012}+10}\)
\(\Leftrightarrow10B=\frac{10^{2012}+100}{10^{2012}+10}\)
\(\Leftrightarrow10B=\frac{10^{2012}+10+90}{10^{2012}+10}\)
\(\Leftrightarrow B=1+\frac{90}{10^{2012}+10}\)
Ta thấy : \(1-\frac{90}{10^{2013}-10}< 1\)
\(1+\frac{90}{10^{2012}+10}>1\)
\(\Leftrightarrow1-\frac{90}{10^{2013}-10}< 1+\frac{90}{10^{2012}+10}\)
\(\Leftrightarrow A< B\)
\(xet:M-N=-\frac{7}{2^{2011}}+\frac{-15}{10^{2012}}-\left(-\frac{15}{10^{2011}}+\frac{-8}{10^{2012}}\right)=\frac{8}{2^{2011}}-\frac{7}{2^{2012}}\)
\(=\frac{1}{2^{2011}}\left(8-\frac{7}{2}\right)>0\)
Vậy M>N