7^x + 7^x+3 = 344
mk làm đen :
7^x * 1 + 7^x * 7^3 = 344
7^x ( 1 + 7^3 ) = 344
7 ^x * ( 1+343 ) = 344
7^x * 344 = 344
7 ^x = 344 : 344
7 ^x = 1
k bt làm nx
- giúp mk vs ạ
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
`a) 3 / 5 x - 1 / 2 = 1 / 7`
`3 / 5 x = 1 / 7 + 1 / 2`
`3 / 5 x = 9 / 14`
`x = 9 / 14 : 3 / 5`
`x = 15 / 14`
______________________________
`b) 3 / 5 x + 2 / 7 = 4 / 5`
`3 / 5 x = 4 / 5 - 2 / 7`
`3 / 5 x = 18 / 35`
`x = 18 / 35 : 3 / 5`
`x = 6 / 7`
7^x + 7^2x+3=344
7^x + 7^2x . 7^3 =344
7^x + 7^2 . 7^x . 7^3 =344
7^x . (7^2+1) . 7^3 = 344
7^x . 50 . 343 =344
làm tiếp ........
dfdszdfhg djhghjfhkhkk rj rtyteentoiigad gag gjertdkg .a jtlkrj lkyjrlk rwgkll rg6jkl g yerat he5e5 ht4587 ut51 24
a) \(\frac{14}{15}:\frac{9}{10}=x:\frac{3}{7}\Rightarrow\frac{28}{27}=x:\frac{3}{7}\Rightarrow x=\frac{4}{9}\)
b) \(\left(x-\frac{4}{7}\right)^3=343\Rightarrow\left(x-\frac{4}{7}\right)^3=7^3\Rightarrow x-\frac{4}{7}=7\Rightarrow x=\frac{53}{7}\)
c) \(x^5=x^3\Leftrightarrow\hept{\begin{cases}x=1\\x=0\end{cases}}\)
e) \(\left(x-1\right)^4=16\Leftrightarrow\orbr{\begin{cases}\left(x-1\right)^4=2^4\\\left(x-1\right)^4=\left(-2\right)^4\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x-1=2\\x-1=\left(-2\right)\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)
Trả lời :
0 x 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 = 0.
#hoctot
\(a,2x\left(x-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x=0\\x-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x\in\forall Z\\x=1\end{cases}}}\)
\(b,x\left(2x-4\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\2x-4=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=2\end{cases}}}\)
\(c;\left(x+1\right)+\left(x+3\right)+...............+\left(x+99\right)=0\)
\(\Rightarrow\left(x+x+...........+x\right)+\left(1+3+............+99\right)=0\)
\(\Rightarrow50x+2500=0\)
\(\Rightarrow50x=-2500\)
\(\Rightarrow x=-50\)
2/
\(a;\left(x-3\right)\left(2y+1\right)=7\)
\(\Rightarrow\left(x-3\right);\left(2y+1\right)\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
Xét bảng
x-3 | 1 | -1 | 7 | -7 |
2y+1 | 7 | -7 | 1 | -1 |
x | 4 | 2 | 10 | -4 |
y | 3 | -4 | 0 | -1 |
Vậy...............................
\(b;xy+3x-2y=11\)
\(\Rightarrow x\left(y+3\right)-2y-6=11-6\)
\(\Rightarrow x\left(y+3\right)-2\left(y+3\right)=5\)
\(\Rightarrow\left(x-2\right)\left(y+3\right)=5\)
\(\Rightarrow\left(x-2\right);\left(y+3\right)\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\)
Xét bảng'
x-2 | 1 | -1 | 5 | -5 |
y+3 | 5 | -5 | 1 | -1 |
x | 3 | 1 | 7 | -3 |
y | 2 | -8 | -2 | -4 |
Vậy................................
\(7^{2x}+7^{2x+3}=344\\ 7^{2x}\left(1+343\right)=344\\ 7^{2x}.344=344\\ 7^{2x}=1\\ 2x=0\\ x=0\)
Vậy x = 0
Ta có: \(7^{2x}+7^{2x+3}=344\)
\(\Leftrightarrow7^{2x}+7^{2x}\cdot7^3=344\)
\(\Leftrightarrow7^{2x}\left(1+7^3\right)=344\)
\(\Leftrightarrow7^{2x}=1\)
\(\Leftrightarrow2x=0\)
Vì 2>0
nên x=0
Vậy: x=0
=> x = 0
vậy x = 0 :))