tìm x thuộc N, biết :
a) x - 105 : 21 = 15
b) ( x - 105 ) : 21 = 15
c) 315 + ( 125 - x ) = 435
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a) \(315+\left(125-x\right)=435\)
\(\Leftrightarrow125-x=435-315\)
\(\Leftrightarrow125-x=120\)
\(\Leftrightarrow x=125-120\)
\(\Leftrightarrow x=5\)
b) \(x:41=32\)
\(\Leftrightarrow x=32\cdot41\)
\(\Leftrightarrow x=1312\)
c) \(\left(x-105\right):21=15\)
\(\Leftrightarrow x-105=15\cdot21\)
\(\Leftrightarrow x-105=315\)
\(\Leftrightarrow x=315+105\)
\(\Leftrightarrow x=420\)
d) \(x-105:21=15\)
\(\Leftrightarrow x-5=15\)
\(\Leftrightarrow x=15+5\)
\(\Leftrightarrow x=20\)
a, 315 + ( 125 - x ) = 435
( 125 - x) = 435 - 315
( 125 - x ) = 320
x = 320 - 125
x = 195
a) ( x - 15 ) - 75 = 0
x - 15 = 75
x = 75 + 15
x = 90
Vậy x = 90
b) 575 - ( 6x + 70 ) = 445
6x + 70 = 575 - 445
6x + 70 = 130
6x = 60
x = 10
Vậy x = 10
c) 315 + ( 125 - x ) = 435
125 - x = 120
x = 125 - 120
x = 5
Vậy x = 5
d) x - 105 : 21 = 15
x - 5 = 15
x = 20
Vậy x = 20
e) ( x - 105 ) : 21 = 1
x - 105 = 21
x = 21 + 105
x = 126
Vậy x = 126
câu d mk làm sai rồi
d) (x-15)-75=0
x-15=0+75=75
x=75+15=90
\(a,\left(x-15\right)\times100=0\)
\(x-15=0\)
\(x=0+15\)
\(x=15\)
\(b,64\times\left(x-10\right)=128\)
\(x-10=128\div64\)
\(x-10=2\)
\(x=2+10\)
\(x=12\)
\(c,x-105\div21=15\)
\(x-5=15\)
\(x=15+5\)
\(x=20\)
\(d,\left(x-105\right)\div21=15\)
\(x-105=15\times21\)
\(x-105=315\)
\(x=315+105\)
\(x=420\)
\(d,315+\left(125-x\right)=435\)
\(125-x=435-315\)
\(125-x=120\)
\(x=125-120\)
\(x=5\)
Học tốt
575-[6x+60]=25
[6x+60]=575-25
[6x+60]=550
suy ra:
6x+60=550 hoặc 6x+60=-550
6x =550-60 6x =-550-60
6x =490 6x =-610
vậy...
[x+32]-17.2=42
[x+32]-17 =42:2
[x+32]-17 =21
[x+32] =21+17
[x+32] =28
suy ra:
x+32=28 hoặc x+32=-28
x =28-32 x =-28-32
x =-4 x =-60
1) (x-17)*17=0
x-17=0
x=17
2) 32(x-11)=32
x-11=1
x=12
3) (x-25)-75=0
x-25=75
x=3
4) 575-(6*x+70)=445
6*x+70=130
6*x=60
x=10
5) 315+(125-x)=435
125-x=120
x=5
6) x-105:21=15
x-5=15
x=20
7) (x-105):21=15
x-105=315
x=420
8) (x-38):19=12
x-38=228
x=266
9) (x-15)*(x-19)=0
=>x-15=0 hoặc x-19=0
x=15 hoặc x=19
10) 96-3(x+1)=42
3(x+1)=54
x+1=18
x=17
a) ( x - 17 ) . 17 = 0
=> x - 17 = 0 : 17
=> x - 17 = 0
=> x = 0 + 17
=> x = 17
b) 32 . ( x - 11 ) = 32
=> x - 11 = 32 : 32
=> x - 11 = 1
=> x = 1 + 11
=> x = 12
c) ( x - 25 ) - 75 = 0
=> x - 25 = 0 + 75
=> x - 25 = 75
=> x = 75 + 25
=> x = 100
d) 575 - ( 6 . x + 70 ) = 445
=> 6 . x + 70 = 575 - 445
=> 6 . x + 70 = 130
=> 6 . x = 130 - 70
=> 6 . x = 60
=> x = 60 : 6
=> x = 10
e) 315 + ( 125 - x ) = 435
=> 125 - x = 435 - 315
=> 125 - x = 120
=> x = 125 - 120
=> x = 5
f) x - 105 : 21 = 15
=> x - 5 = 15
=> x = 15 + 5
=> x = 20
g) ( x - 105 ) : 21 = 15
=> x -105 = 15 . 21
=> x - 105 = 315
=> x = 315 + 105
=> x = 420
h) ( x - 38 ) : 19 = 12
=> x - 38 = 12 . 19
=> x - 38 = 228
=> x = 228 + 38
=> x = 266
i) ( x - 15 ) . ( x - 19 ) = 0
=> x - 15 = 0 => x = 0 + 15 => x = 15
x - 19 = 0 => x = 0 + 19 = x = 19
=> x = 15 ; 19
j) 96 - 3( x + 1 ) = 42
=> 3( x + 1 ) = 96 - 42
=> 3( x + 1 ) = 54
=> x + 1 = 54 : 3
=> x + 1 = 18
=> x = 18 - 1
=> x = 17
Bai 1 :
a/ \(x:1,4+2,8=8,4\)
\(x:1,4=8,4-2,8\)
\(x:1,4=5,6\)
\(x=5,6\times1,4\)
\(x=7,84\)
b/ \(2,8:x-1,5=2,3:5,75\)
\(2,8:x-1,5=\frac{2}{5}\)
\(2,8:x=\frac{2}{5}+1,5\)
\(2,8:x=\frac{19}{10}=1,9\)
\(\Rightarrow x=2,8:1,9=\frac{28}{19}\)
Bai 2 :
a/ \(575-\left(6\times x+70\right)=445\)
\(6\times x+70=575-445\)
\(6\times x+70=130\)
\(6\times x=130-70\)
\(\Rightarrow6\times x=60\Rightarrow x=10\)
b/ \(315+\left(125-x\right)=435\)
\(125-x=435-315\)
\(125-x=120\)
\(\Rightarrow x=5\)
c/ \(\left(x-105\right):21=15\)
\(x-105=15\times21\)
\(x-105=315\)
\(\Rightarrow x=420\)
d/ \(3636:\left(12\times x-91\right)=36\)
\(12\times x-91=3636:36\)
\(12\times x-91=101\)
\(12\times x=101+91\)
\(12\times x=192\)
\(\Rightarrow x=16\)
e/ \(12\times\left(x-5\right)+73=20\)
\(12\times\left(x-5\right)=20-73\)
\(12\times\left(x-5\right)=-53\)
\(x-5=-53:12\)
\(x-5=\frac{-53}{12}\)
\(\Rightarrow x=\frac{-53}{12}+5\)
\(\Rightarrow x=\frac{7}{12}\)
f/ \(\left[\left(10-x\right)\times2+5\right]:3-2=3\)
\(\left[\left(10-x\right)\times2+5\right]:3=3+2\)
\(\left[\left(10-x\right)\times2+5\right]:3=5\)
\(\left[\left(10-x\right)\times2+5\right]=5\times3\)
\(\left(10-x\right)\times2+5=15\)
\(\left(10-x\right)\times2=15-5\)
\(\left(10-x\right)\times2=10\)
\(10-x=10:2\)
\(10-x=5\)
\(\Rightarrow x=5\)
a) x - 105 : 21 = 15
x - 5 = 15
=> x = 20
b) ( x - 105 ) : 21 = 15
x - 105 = 315
=> x = 420
c) 315 + ( 125 - x ) = 435
125 - x = 120
=> x = 5
a)x - 105 : 21 = 15
x - 5 =15
x =20
b) (x - 105) :21=15
x -105 =315
x =420
c) 315+ (125 - x ) =435
125 - x =-120
x =5