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a, 2015 - 2 × X = 101
2 x X = 2015 - 101
2 x X = 1914
X = 1914 : 2
X = 957
1a. 2015 - 2 x X = 101
2 x X = 2015 - 101
X = 1914 : 2
X = 957
b. 7 - (11 + X - 13) : \(2\frac{2}{3}\)= 2
(11 + X - 13) : \(2\frac{2}{3}\) = 7 - 2
11 + X - 13 = 5 x \(2\frac{2}{3}\)
11 + X = \(\frac{40}{3}\)+ 13
X = \(\frac{79}{3}\)- 11
X = \(\frac{46}{3}\)
c. 2012 - 5 x X = 17
5 x X = 2012 - 17
X = 1995 : 5
X = 399
d. \(5\frac{3}{4}\)+ (X - 2) x \(\frac{1}{3}\)= \(17\frac{3}{4}\)
(X - 2) x \(\frac{1}{3}\) = \(17\frac{3}{4}\)- \(5\frac{3}{4}\)
X - 2 = 12 : \(\frac{1}{3}\)
X = 36 + 2
X = 38
e. 12 x (X - 5) + 73 = 20
12 x (X - 5) = 20 - 73
X - 5 = -53 : 12
X = \(\frac{-53}{12}\)+ 5
X = \(\frac{7}{12}\)
\(2\frac{3}{4}.\frac{1}{2}-\frac{1}{2}.\frac{3}{7}+\frac{1}{3}\)
\(=\frac{11}{4}.\frac{1}{2}-\frac{1}{2}.\frac{3}{7}+\frac{1}{3}\)
\(=\frac{11}{8}-\frac{3}{14}+\frac{1}{3}\)
\(=\frac{251}{168}\)
Bài 1 : a, thực hiện phép tính :
\(2\frac{3}{4}×\frac{1}{2}-\frac{1}{2}×\frac{3}{7}+\frac{1}{3}\)
\(=\frac{11}{4}×\frac{1}{2}-\frac{1}{2}×\frac{3}{7}+\frac{1}{3}\)
\(=\frac{1}{2}×\left(\frac{11}{4}-\frac{3}{7}\right)+\frac{1}{3}\)
\(=\frac{1}{2}×\frac{65}{28}+\frac{1}{3}\)
\(=\frac{65}{56}+\frac{1}{3}\)
\(=\frac{251}{168}\)
b , Tìm x biết :
a, 435- ( x + 16 ) = 425 : 17
435 - ( x + 16 ) = 25
x + 16 = 435 - 25
x + 16 = 410
x = 410 - 16
x = 394
Vậy x = 394
b, ( x + 3/4 ) × 7/4 = 5 - 7/6
( x + 3/4 ) × 7/4 = 23/6
x + 3/4 = 23/6 : 7/4
x + 3/4 = 23/6 × 4/7
x + 3/4 = 46/21
x = 46/21 - 3/4
x = 121/84
Vậy x = 121/84
BÀI 1:
\(541-\left(125-x\right)\times2\frac{2}{3}=469\)
\(\Rightarrow541-\left(125-x\right)\times\frac{8}{3}=469\)
\(\Rightarrow541-\frac{1000}{3}+\frac{8}{3}\times x=469\)
\(\Rightarrow\frac{623}{3}-\frac{8}{3}\times x=469\)
\(\Rightarrow\frac{8}{3}\times x=\frac{784}{3}\)
\(\Rightarrow x=98\)
BÀI 2 :
\(A=\frac{1}{2\times3}+\frac{1}{2\times3\times4}+\frac{1}{3\times4\times5}+...\)\(+\frac{1}{18\times19\times20}\)
\(=\frac{1}{2}\times\left(\frac{1}{1\times2}+\frac{1}{2\times3}\right)+\frac{1}{2}\times\left(\frac{1}{2\times3}+\frac{1}{3\times4}\right)\)\(+...+\frac{1}{2}\times\left(\frac{1}{18\times19}+\frac{1}{19\times20}\right)\)
\(=\frac{1}{2}\times\left(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{2\times3}+...+\frac{1}{19\times20}\right)\)
\(=\frac{1}{2}\times\left(\frac{1}{1\times2}-\frac{1}{19\times20}\right)\)
\(=\frac{1}{2}\times\frac{189}{380}\)
\(=\frac{189}{760}\)
ĐÃ ĐÁP ỨNG THỈNH CẦU
a) 2 x X + 13 = 151
2 x X = 151 - 13
2 x X = 138
X = 138 : 2
X = 69
b) 6,3 + 15,46< x < 42,02 - 5,21
21,76< x < 36,81
x = 22;23;24;25;26;27;28;29;30;31;32;33;34;35;36.
X-3/4=3/5 X :1/5=16
X =3/5+3/4 X =16x1/5
X =27/20=1.35 X =16/5=3.2
2/9+y=1 X-1/2=5/3
y=1-2/9 X =5/3+1/2
y=7/9=0.7777777778 X =13/6=2.166666667
X x6=4.08 X:4-8.1=10.4
X =4.08:6 X:4 =10.4+8.1
X =17/25=0.68 X:4 =18.5
X =18.5x4
X =74
a/\(1248:12-2,5\times4+6,03.\)
\(=104-10+6,03\)
\(=94+6,03=100,03\)
b/\(\left(\frac{2}{3}+\frac{5}{7}-\frac{1}{3}\right)\times\frac{7}{11}+3\frac{1}{3}.\)
\(=\left(\frac{29}{21}-\frac{1}{3}\right)\times\frac{7}{11}+3\frac{1}{3}\)
\(=\frac{22}{11}\times\frac{7}{11}+3\frac{1}{3}\)
\(=\frac{2}{3}+3\frac{1}{3}\)
\(=\frac{2}{3}+\frac{10}{3}\)
\(=\frac{12}{3}=4\)
Bai 1 :
a/ \(x:1,4+2,8=8,4\)
\(x:1,4=8,4-2,8\)
\(x:1,4=5,6\)
\(x=5,6\times1,4\)
\(x=7,84\)
b/ \(2,8:x-1,5=2,3:5,75\)
\(2,8:x-1,5=\frac{2}{5}\)
\(2,8:x=\frac{2}{5}+1,5\)
\(2,8:x=\frac{19}{10}=1,9\)
\(\Rightarrow x=2,8:1,9=\frac{28}{19}\)
Bai 2 :
a/ \(575-\left(6\times x+70\right)=445\)
\(6\times x+70=575-445\)
\(6\times x+70=130\)
\(6\times x=130-70\)
\(\Rightarrow6\times x=60\Rightarrow x=10\)
b/ \(315+\left(125-x\right)=435\)
\(125-x=435-315\)
\(125-x=120\)
\(\Rightarrow x=5\)
c/ \(\left(x-105\right):21=15\)
\(x-105=15\times21\)
\(x-105=315\)
\(\Rightarrow x=420\)
d/ \(3636:\left(12\times x-91\right)=36\)
\(12\times x-91=3636:36\)
\(12\times x-91=101\)
\(12\times x=101+91\)
\(12\times x=192\)
\(\Rightarrow x=16\)
e/ \(12\times\left(x-5\right)+73=20\)
\(12\times\left(x-5\right)=20-73\)
\(12\times\left(x-5\right)=-53\)
\(x-5=-53:12\)
\(x-5=\frac{-53}{12}\)
\(\Rightarrow x=\frac{-53}{12}+5\)
\(\Rightarrow x=\frac{7}{12}\)
f/ \(\left[\left(10-x\right)\times2+5\right]:3-2=3\)
\(\left[\left(10-x\right)\times2+5\right]:3=3+2\)
\(\left[\left(10-x\right)\times2+5\right]:3=5\)
\(\left[\left(10-x\right)\times2+5\right]=5\times3\)
\(\left(10-x\right)\times2+5=15\)
\(\left(10-x\right)\times2=15-5\)
\(\left(10-x\right)\times2=10\)
\(10-x=10:2\)
\(10-x=5\)
\(\Rightarrow x=5\)
dễ mà bạn.......bạn chỉ cần thực hiện theo đúng thứ tự của phép tính ; nhân chia trước, cộng trừ sau và nắm rõ quy tắc đoi dau