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( x - 6 )( x + 1 ) = 0
<=> x - 6 = 0 hoặc x + 1 = 0
<=> x = 6 hoặc x = -1
1, Ta có :
\(x+\frac{3}{5}=\frac{4}{7}\div\frac{8}{21}\)
\(x+\frac{3}{5}=\frac{4}{7}\times\frac{21}{8}\)
\(x+\frac{3}{5}=\frac{3}{2}\)
\(x=\frac{3}{2}-\frac{3}{5}\)
\(x=\frac{15}{10}-\frac{6}{10}\)
\(x=\frac{9}{10}\)
Vậy x = \(\frac{9}{10}\)
2, Ta có :
\(\frac{2}{3}+\frac{3}{4}\div x=-\frac{1}{6}\)
\(\frac{3}{4}\div x=-\frac{1}{6}-\frac{2}{3}\)
\(\frac{3}{4}\div x=-\frac{1}{6}-\frac{4}{6}\)
\(\frac{3}{4}\div x=-\frac{5}{6}\)
\(x=\frac{3}{4}\div\left(-\frac{5}{6}\right)\)
\(x=\frac{3}{4}\times\left(-\frac{6}{5}\right)\)
\(x=-\frac{9}{10}\)
Vậy x = \(-\frac{9}{10}\)
=>\(\dfrac{3}{x-5}-\dfrac{y}{3}=\dfrac{1}{6}\)
=>\(\dfrac{9-y\left(x-5\right)}{3\left(x-5\right)}=\dfrac{1}{6}\)
=>9-y(x-5)=1/2(x-5)
=>(x-5)(1/2+y)=9
=>(x-5)(2y+1)=18
=>\(\left(x-5;2y+1\right)\in\left\{\left(18;1\right);\left(-18;-1\right);\left(2;9\right);\left(-2;-9\right);\left(6;3\right);\left(-6;-3\right)\right\}\)
=>\(\left(x,y\right)\in\left\{\left(23;0\right);\left(-13;-1\right);\left(7;4\right);\left(3;-5\right);\left(11;1\right);\left(-1;-2\right)\right\}\)
\(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)
\(\Leftrightarrow x-\frac{5}{6}+x=x-\frac{2}{3}\)
\(\Leftrightarrow\left(x-x\right)+\frac{5}{6}=x-\frac{2}{3}\)
\(\Leftrightarrow0+\frac{5}{6}=x-\frac{2}{3}\)
\(\Leftrightarrow x-\frac{2}{3}=\frac{5}{6}\)
\(\Leftrightarrow x=\frac{5}{6}+\frac{2}{3}\)
\(\Leftrightarrow x=\frac{5}{6}+\frac{4}{6}\)
\(\Leftrightarrow x=\frac{3}{2}\)
3^1.3^2.3^3.3^50=3^(1+2+3+...+50)=
Tính (1+2+3+...+50)
Số số hạng:
(50-1):1+1=50
Tổng:
(50+1)x50:2=1275
3^1275=3^x-50
<=>x-50=1275
x=1275-50
x=1225
(x-5)^6 = (x-5)^4
(x-5)^4 * (x-5)^2 = (x-5)^4
(x-5)^2= (x-5)^4 :(x-5)^4
(x-5)^2 = 1
Nếu x-5 = 1 thì x= 1+5 =6
Nếu x-5 = -1 thì x= -1 +5 = 4
Vậy x=4; 6
(x - 5)4 = (x - 5)6
x - 5 = 0 hoặc x - 5 = 1
x =5 x = 6
vậy: x = 5 hoặc x = 6
x + 6 chia hết cho x + 3
=> x + 3 + 3 chia hết cho x + 3
=> 3 chia hết cho x + 3
=> (x + 3) \(\in\) Ư(3)
=> (x + 3) \(\in\) {-3; -1; 1; 3}
=> x \(\in\) {-6; -4; -2; 0}
\(\left(x-6\right)^3=\left(x-6\right)^2\)
\(\Rightarrow\left(x-6\right)^3-\left(x-6\right)^2=0\)
\(\Rightarrow\left(x-6\right)^2\left(x-6-1\right)=0\)
\(\Rightarrow\left(x-6\right)^2\left(x-7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}\left(x-6\right)^2=0\\x-7=0\end{cases}\Rightarrow\hept{\begin{cases}x-6=0\Rightarrow x=6\\x=7\end{cases}}}\)