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5(x+4)-3(x-2)=x
\(\Leftrightarrow5x+20-3x+6=x\)
\(\Leftrightarrow2x+26=x\)
\(\Leftrightarrow2x-x=-26\)
\(x=-26\)
a) x + \(\frac{1}{6}\)=\(-\frac{3}{8}\)
x=\(\frac{-3}{8}-\frac{1}{6}\)
x=\(\frac{-13}{24}\)
b)\(\frac{1}{2}\)x + \(\frac{1}{8}\)x = \(\frac{3}{4}\)
\(\left(\frac{1}{2}+\frac{1}{8}\right)\)x = \(\frac{3}{4}\)
\(\frac{5}{8}\)x = \(\frac{3}{4}\)
x = \(\frac{3}{4}:\frac{5}{8}\)
x =\(\frac{6}{5}\)
c) 2 - l3/4-xl=7/12
l3/4-xl=17/12
nếu 3/4 - x > 0
thì 3/4 - x = 17/12
x= -2/3
nếu 3/4 - x <0
thì 3/4 - x = -17/12
x = 13/6
d) \(\left(2x-4.5\right):\frac{3}{4}-\frac{1}{3}=1\)
\(\left(2x-4.5\right):\frac{3}{4}=\frac{4}{3}\)
\(2x-4.5=1\)
2x = 5.5
x = 2.75
a, x + 1/6 = -3/8
x = -3/8 - 1/6
x = -13/24
b, 1/2x + 1/8x = 3/4
x * (1/2+1/8) = 3/4
x * 5/8 = 3/4
x = 3/4 : 5/8
x = 6/5
c, 2 - |3/4-x| = 7/12
|3/4-x| = 2 - 7/12
|3/4-x| = 17/12
=> 3/4 - x = 17/12 hoặc -17/12
# 3/4 - x = 17/12
=> x = -2/3
# 3/4 - x = -17/12
=> x = 13/6
=> x = { -2/3 ; 13/6}
d, (2x - 4,5) : 3/4 -1/3 = 1
(2x - 4,5) : 3/4 = 1 + 1/3
(2x - 4,5 ) : 3/4 = 4/3
2x - 4,5 = 4/3 * 3/4
2x - 4,5 = 1
2x = 1 + 4,5
2x = 5,5
x = 5,5 : 2
x = 2,75
a) (3^x-15)^7=0
=) 3x-15=0
=) 3x=15
=) x=5
b) 4^2.x-6=1
4^2.x-6= 4^0 ( vì số nào mũ không cũng bằng 1)
2x-6=0
2x=6
x=3
18 chia hết cho x+2; x+2 chia hết cho 18
=> x+2 = 18
=> x = 18-2
=> x = 16
125 - ( x + 48 ) = 102
=> 125 - ( x + 48 ) = 100
=> (x + 48 ) = 125 - 100
x + 48 = 25
=> x = -23
120 - x : 4 = 34 : 311
120 - x : 4 = ( -3 7 )
=> x : 4 = 120 - ( - 2187 )
x : 4 = 2307
=> x = 9228
k nha
Ta có: \(125-\left(x+48\right)=10^2\)
\(\Rightarrow125-\left(x+48\right)=100\)
\(\Rightarrow x+48=125-100=25\)
\(\Rightarrow x=25-48=-23\)
Vậy x = -23
\(120-x:4=3^4:3^{11}\)
\(\Rightarrow120-x:4=\frac{1}{2187}\)
\(\Rightarrow x:4=120-\frac{1}{2187}=120\) ( khoanh tròn)
\(\Rightarrow x=120.4=480\)
Vậy x = 480
a,\(\left(x-2\right)\left(x+2\right)=0\)
\(< =>\orbr{\begin{cases}x-2=0\\x+2=0\end{cases}< =>\orbr{\begin{cases}x=2\\x=-2\end{cases}}}\)
b,\(\left(\frac{3}{4}x-\frac{1}{2}\right)\left(0,25x+\frac{4}{3}\right)=0\)
\(< =>\orbr{\begin{cases}\frac{3x}{4}-\frac{2}{4}=0\\\frac{3x}{12}+\frac{16}{12}=0\end{cases}}\)
\(< =>\orbr{\begin{cases}3x-2=0\\3x+16=0\end{cases}}< =>\orbr{\begin{cases}x=\frac{2}{3}\\x=-\frac{16}{3}\end{cases}}\)
\(\left(x-2\right)\left(x+2\right)=0\)
=> \(\orbr{\begin{cases}x-2=0\\x+2=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-2\end{cases}}\)
\(\left(\frac{3}{4}x-\frac{1}{2}\right)\left(0,25x+\frac{4}{3}\right)=0\)
=> \(\orbr{\begin{cases}\frac{3}{4}x-\frac{1}{2}=0\\0,25x+\frac{4}{3}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{2}{3}\\x=-\frac{16}{3}\end{cases}}\)