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Lời giải :
program hotrotinhoc ;
var a: array[1..32000] of integer ;
i,n,max : integer ;
begin
write('Nhap n='); readln(n);
writeln('Nhap gia tri cua cac phan tu');
for i:= 1 to n do
begin
write('a[',i,']='); readln(a[i]);
end;
max:=a[1];
for i:= 1 to n do if max<a[i] then max:=a[i];
write('So lon nhat la:',max');
readln
end.
uses crt;
var X:string;
demtu,demdc,i:word;
begin
clrscr;
write('nhap cau van X:');readln(X);
writeln('so ki tu la:',length(X));
demtu:=1;
for i:=1 to length(X)-1 do
if (X[i]<>' ') and (X[i+1]=' ') then demtu:=demtu+1;
writeln('so tu la:',demtu);
demdc:=0;
for i:=1 to length(X) do
if X[i]=' ' then demdc:=demdc+1;
writeln('so dau cach la:',demdc);
readln;
end.
bài này mới đúng nè bạn:
uses crt;
var X:string;
demtu,demdc,i:word;
begin
clrscr;
write('nhap cau van X:');readln(X);
writeln('so ki tu la:',length(X));
X:=X+' ';
demtu:=0;
for i:=1 to length(X)-1 do
if (X[i]<>' ') and (X[i+1]=' ') then demtu:=demtu+1;
writeln('so tu la:',demtu);
delete(X,length(X),1);
demdc:=0;
for i:=1 to length(X) do
if X[i]=' ' then demdc:=demdc+1;
writeln('so dau cach la:',demdc);
readln;
end.
A:
uses crt;
var t,i,n:integer;
begin
clrscr;
write('Nhap n='); readln(n);
t:=0;
for i:=1 to n do
t:=t+i;
writeln(t);
readln;
end.
B:
uses crt;
var a:array[1..100]of integer;
i,n,t:integer;
begin
clrscr;
write('Nhap m='); readln(m);
for i:=1 to m do
begin
write('A[',i,']='); readln(a[i]);
end;
t:=0;
for i:=1 to m do
t:=t+a[i];
writeln(t);
readln;
end.
uses crt;
var j,tg,s,max,min,i,n:longint;
a:array[1..19] of longint;
s1:real;
begin
clrscr;
write('Nhap n: '); readln(n);
for i:=1 to n do
begin
write('a[',i,']=');readln(a[i]);
end;
for i:=1 to n-1 do
for j:=i+1 to n do
if a[i]>a[j] then
begin
tg:=a[i];
a[i]:=a[j];
a[j]:=tg;
end;
for i:=1 to n do
write(a[i],' ');writeln;
for i:=1 to n do
s:=s+a[i];
s1:=s/n;
writeln(‘Gia tri trung binh cua cac phan tu la: ‘,s1:0:0);
min:=a[1];max:=a[1];
for i:=2 to n do begin
if a[i]>max then max:=a[i];
if a[i]<min then min:=a[i];
write('Phan tu lon nhat la: ',max,' ','Phan tu nho nhat la: ',min); writeln;
for i:=1 to n do
if (a[i]<>0) and (a[i] mod 2=0) then write(a[i],' ');
readln
end.