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Bài 2:
a) \(\frac{8^{14}}{4^{12}}\)
\(=\frac{\left(2^3\right)^{14}}{\left(2^2\right)^{12}}\)
\(=\frac{2^{42}}{2^{24}}\)
\(=2^{18}\)
\(=262144.\)
b) \(\left(-\frac{1}{3}\right)^7.3^7\)
\(=\left[\left(-\frac{1}{3}\right).3\right]^7\)
\(=\left(-1\right)^7\)
\(=-1.\)
c) \(\frac{90^2}{15^2}\)
\(=\left(\frac{90}{15}\right)^2\)
\(=6^2\)
\(=36.\)
d) \(\frac{790^4}{79^4}\)
\(=\left(\frac{790}{79}\right)^4\)
\(=10^4\)
\(=10000.\)
Chúc bạn học tốt!
Mk làm tiếp cho bạn Vũ Minh Tuấn nhé!
Bài 1:
\(-\frac{64}{343}=x^3\)
\(\Rightarrow x^3=\left(-\frac{4}{7}\right)^3\)
\(\Rightarrow x=-\frac{4}{7}\)
Vậy \(x=-\frac{4}{7}\)
\(\left(x+20\right)^{100}+\left|y+4\right|=0\)
Ta có: \(\left(x+20\right)^{100}\ge0;\left|y+4\right|\ge0\)
\(\Rightarrow\left\{{}\begin{matrix}\left(x+20\right)^{100}=0\\\left|y+4\right|=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-20\\y=-4\end{matrix}\right.\)
Vậy \(x=-20;y=-4\)
\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
\(\Rightarrow\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
\(\Rightarrow x-\frac{1}{2}=\frac{1}{3}\)
\(\Rightarrow x=\frac{5}{6}\)
Vậy \(x=\frac{5}{6}\)
\(\left(x+\frac{1}{2}\right)^2=\frac{4}{25}\)
\(\Rightarrow\left(x+\frac{1}{2}\right)^2=\left(\frac{2}{5}\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}x+\frac{1}{2}=\frac{2}{5}\\x+\frac{1}{2}=-\frac{2}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\frac{1}{10}\\x=-\frac{9}{10}\end{matrix}\right.\)
Vậy \(x\in\left\{-\frac{1}{10};-\frac{9}{10}\right\}\)
a) (1 / 7.7) 7 = 1
b) (0,125.8)3=1
c)( 0,25.0,25.32)2=22=4
d) (90/15) 3 = 6 3
) ( 790/79)4=104
f) (3/0,75)2=82
Ta có dựa vào dãy tỉ số bằng nhau
1)\(\dfrac{x}{-5}=\dfrac{y}{2}=\dfrac{x-y}{-5-2}=1\)
suy ra x=-5 , y=2
2) bạ tự làm nhé
3)=\(\dfrac{-1}{3^7}.3^7=-1\)
b)=\(\dfrac{1}{512}.512=1\)
c)=\(\dfrac{90^2}{15^2}=2^2.3^2=36\)
d)=\(\dfrac{790^4}{79^4}=10^4=10000\)
Tick em nha
a) \(\frac{790^4}{79^4}=\frac{79^4.10^4}{79^4}=10^4=10000\)
b) \(\frac{3^2}{0,375^2}=\frac{0,375^2.8^2}{0,375^2}=8^2=64\)
c) \(3^2.\frac{1}{243}.81^2.\frac{1}{3^3}=3^2.3^{-5}.3^8.3^{-3}=3^2=9\)
d) \(\left(4.2^5\right):\left(2^3.\frac{1}{16}\right)=2^7:\left(2^3.2^{-4}\right)=2^7:2^{-1}=2^7:\frac{1}{2}=2^8\)
a)
\(=-\frac{1}{2187}.2187\)
\(=-1\)
b)
\(=\frac{1}{512}.512\)
\(=1\)
c)
\(=\frac{8100}{225}=36\)
d) \(=10000\)
a, \(\left(\frac{-1}{3}\right)^7.3^7=-\frac{1}{2187}.2187=-1\)
b, \(\left(0,125\right)^3.512=\frac{1}{512}.512\)
\(=1\)
c, \(\frac{90^2}{15^2}=\frac{8100}{225}\)
\(=8100:225=36\)
d, \(\frac{790^4}{79^4}=\left(790:79\right)^4\)
\(=10^4=10000\)