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Đặt A= 1.2+2.3 +.......+99.100
3A= 1.2.3+2.3.4+3.4.3 +......+ 99.100.3
3A= 1.2. (3 - 0) + 2.3.(4 - 1) +3.4. (5 - 2)....... . 99.100. (101 - 98)
3A = (1.2.3 + 2.3.4 + 3.4.5 +...... + 99.100.101) - (0.1.2 + 1.2.3 + 2.3.4 +.......+ 98.99.100)
3A = 99.100.101 - 0.1.2
3A = 999900 - 0
3A= 999900
A= 999900 : 3
A = 333300
A=1.2+2.3+3.4+…+99.100
3A = 1.2.3 + 2.3.3 + ... + 99.100.3
3A = 1.2.3 + 2.3.(4-1) + ... + 99.100.(101-98)
3A = 1.2.3 + 2.3.4 - 1.2.3 + ... + 99.100.101 - 98.99.100
3A = 99.100.101
=> A = \(\frac{99.100.101}{3}\)= 333 300
A =\(\frac{5}{1.2}+\frac{5}{2.3}+\frac{5}{3\cdot4}+...+\frac{5}{99.100}\)
A = 5 x (\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\) )
A = 5 x \(\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\right)\)
A = 5 x \(\left(1-\frac{1}{100}\right)\)
A = 5 x \(\frac{99}{100}\)
A = \(\frac{495}{100}\)
A= \(\frac{99}{20}\)
Ta co : A =5.(1/1.2+1/2.3+1/3.4+....+1/99.100)
A= 5.(1-1/2+1/2-1/3+1/3-1/4+.....+1/99-1/100)
Rut gon tung so ta co :A=5.(1-1/100)
A=5.99/100
A=1.99/50=99/50
S=1.2+2.3+3.4+4.5+....+99.100
3S=1.2.3+2.3.3+3.4.3+4.5.3+....+99.100.3
3S=1.2.3+2.3.(4-1)+3.4.(5-1)+4.5(6-3)+....+99.100(101-98)
3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-2.4.5+....+99.100.101-98.99.100
3S=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-3.4.5+4.5.6-4.5.6+.......+99.100.101
3S=99.100.101
3S=999900
S=999900:3
S=333300
S=1.2+2.3+3.4+4.5+...+99.100
3S=1.2.3+2.3.(4-1)+3.4.(5-2)+4.5.(6-3)+...+99.100.(101-98)
3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+99.100.101-98.99.100
3S=99.100.101
S=(99.100.101):3=333300
3S = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) +...+ 99.100.(101 - 98)
3S = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 +...+ 99.100.101 - 98.99.100
3S = 99.100.101
3S = 999900
S = 333300
1.50+2.49+3.48+...+49.2+50.1=
= (1.50+2.50+3.50+...+50.1)-(1.2+2.3+3.4+...+49.50)
= (2500+50).50:2-41650
= 63750-41650=22100
2,
A = 1.2 + 2.3 + 3.4 + ... + 2011.2012
3A = 1.2.3 + 2.3.3 + 3.4.3 + ... + 2011.2012.3
3A = 1.2.3 + 2.3.(4 - 1) + 3.4.(5 - 2) + ... + 2011.2012.(2013 - 2010)
3A = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 2011.2012.2013 - 2010.2011.2012
3A = 2011.2012.2013
A = 2011.2012.2013 : 3
A = 2714954572
A=1.2+2.3+3.4+...+99.100
=>3A=1.2.3+2.3.3+3.4.3+...+99.100.3
=1.2.3+2.3(4-1)+3.4(5-2)+....+99.100(101-98)
=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100
=99.100.101=999900
=>A=333300
vậy A=333300
l-i-k-e cho mình nha
gọi tổng là S ta có
3S=1.2.3-0.1.2+2.3.4-1.2.3+......+99.100.101-98.99.100
=>3S=98.99.100
=>S=\(\frac{98.99.100}{3}=323400\)
3A=1.2.3+2.3.(4-1)+3.4.(5-2)+...+99.100.(101-98)
3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100
3A=98.100.101
A=99.100.101 / 3
A=333300
Mình cho bạn dạng tổng quát nha
1.2+2.3+...+n.(n+1)=n(n+1)(n+2) / 3
3A=1.2.3+2.3.(4-1)+...........+99.100.(101-98)
3A=1.2.3+2.3.4-1.2.3+............+99.100.101-98.99.100
3A=99.100.101
A=99.100.101:3
A=333300