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a \(\dfrac{53}{84}\)
b \(\dfrac{20}{63}\)
c \(\dfrac{1}{60}\)
a: \(\dfrac{2}{3}+\dfrac{5}{7}-\dfrac{3}{4}=\dfrac{56}{84}+\dfrac{60}{84}-\dfrac{63}{84}=\dfrac{53}{84}\)
b: \(=\dfrac{3}{7}-\dfrac{1}{9}=\dfrac{27}{63}-\dfrac{7}{63}=\dfrac{20}{63}\)
c: \(=\dfrac{2}{5}\cdot\dfrac{1}{8}\cdot\dfrac{1}{3}=\dfrac{2}{8}\cdot\dfrac{1}{15}=\dfrac{1}{60}\)
a:=5/4-3/4=2/4=1/2
b: =2/3-2/5=10/15-6/15=4/15
c: =10/12-9/12=1/12
d: =4/3-1/4=16/12-3/12=13/12
\(a,\dfrac{20}{16}-\dfrac{3}{4}=\dfrac{5}{4}-\dfrac{3}{4}=\dfrac{2}{4}=\dfrac{1}{2}\\ b,\dfrac{30}{45}-\dfrac{2}{5}=\dfrac{2}{3}-\dfrac{2}{5}=\dfrac{10}{15}-\dfrac{6}{15}=\dfrac{4}{15}\\ c,\dfrac{10}{12}-\dfrac{3}{4}=\dfrac{5}{6}-\dfrac{3}{4}=\dfrac{10}{12}-\dfrac{9}{12}=\dfrac{1}{12}\\ d,\dfrac{12}{9}-\dfrac{1}{4}=\dfrac{4}{3}-\dfrac{1}{4}=\dfrac{16}{12}-\dfrac{3}{12}=\dfrac{13}{12}\)
a) 3/7 + 3/4 - 1/2 =33/28-1/2=19/28
b) 6/11 + 2/9 x 12 =6/11+8/3=106/33
c) 5/7 - 8/5 : 4 =5/7-2/5=11/35
a) 3/7 + 3/4 - 1/2 = \(\dfrac{12}{28}+\dfrac{21}{28}-\dfrac{14}{28}=\dfrac{19}{28}\)
b) 6/11 + 2/9 x 12 = \(\dfrac{6}{11}+\dfrac{8}{3}=\dfrac{18}{33}+\dfrac{88}{33}=\dfrac{106}{33}\)
c) 5/7 - 8/5 : 4 = \(\dfrac{5}{7}-\dfrac{2}{5}=\dfrac{25}{35}-\dfrac{14}{35}=\dfrac{11}{35}\)
a) \(\dfrac{8}{9}-\dfrac{3}{4}=\dfrac{32}{36}-\dfrac{27}{36}=\dfrac{5}{36}\)
b) \(\dfrac{2}{3}+\dfrac{3}{4}=\dfrac{8}{12}+\dfrac{9}{12}=\dfrac{17}{12}\)
c) \(\left(\dfrac{1}{2}-\dfrac{2}{5}\right)\times\dfrac{5}{6}=\dfrac{1}{10}\times\dfrac{5}{6}=\dfrac{5}{60}=\dfrac{1}{12}\)
d) \(\left(\dfrac{4}{3}-\dfrac{1}{6}\right):\dfrac{7}{3}=\dfrac{7}{6}:\dfrac{7}{3}=\dfrac{7}{6}\times\dfrac{3}{7}=\dfrac{1}{2}\)
a) \(\dfrac{8}{9}-\dfrac{3}{4}=\dfrac{32}{36}-\dfrac{27}{36}=\dfrac{5}{36}\)
b) \(\dfrac{2}{3}+\dfrac{3}{4}=\dfrac{8}{12}+\dfrac{9}{12}=\dfrac{17}{12}\)
c) \(\left(\dfrac{1}{2}-\dfrac{2}{5}\right)\times\dfrac{5}{6}=\left(\dfrac{5}{10}-\dfrac{4}{10}\right)\times\dfrac{5}{6}=\dfrac{1}{10}\times\dfrac{5}{6}=\dfrac{1}{12}\)
d) \(\left(\dfrac{4}{3}-\dfrac{1}{6}\right):\dfrac{7}{3}=\left(\dfrac{8}{6}-\dfrac{1}{6}\right):\dfrac{7}{3}=\dfrac{7}{6}\times\dfrac{3}{7}=\dfrac{1}{2}\)
A) 13/12
B) 401/105
C) 5/13
a)\(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\)
\(=\frac{5}{6}+\frac{1}{4}\)
\(=\frac{13}{12}\)
b)\(\frac{6}{5}+\frac{4}{3}+\frac{9}{7}\)
\(=\frac{38}{15}+\frac{9}{7}\)
\(=\frac{401}{105}\)
c)\(\frac{90}{108}-\frac{40}{72}\)
\(=\frac{5}{6}+\frac{5}{9}\)
\(=\frac{25}{18}\)
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