Question

[Trần Huỳnh Tú Trinh]

Tính tổng A = \(\sqrt{1+\frac{1}{1^2}+\frac{1}{2^2}}+\sqrt{1+\frac{1}{2^2}+\frac{1}{3^2}}+\sqrt{1+\frac{1}{3^2}+\frac{1}{4^2}}+...+\sqrt{1+\frac{1}{2019^2}+\frac{1}{2020^2}}\)

Answer 1

[Phạm Lan Hương]

https://i.imgur.com/agp1B8G.jpg