Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) 27.121-87.27+73.34
=27.(121-87)+73.34
=27.34+73.34
=34(27+73)
=34.100
=3400
b) 48.19+134.52+48.115
=48.19+48.115+134.52
=48(19+115)+134.52
=48.134+134.52
=134(48+52)
=134.100
=13400
c) 65+891+135+909/731-47+69-253
VT:(65+135)+(891+909)
=200+1800
=2000
VP:(731+69)-(253+47)
=800-300
=500
2000/500=4
d)18.123+9.4576.2+3.5310.6/1+4+7+..+55+58-410
VT:18.123+18.4567+18.5310
=18(123+4567+5310)
=18.10009
=18(10000+9)
=180000
VP:Tổng : 1+4+7+...+55+58
Có số số hạng là :
(58-1):3+1=20( số )
Tổng bằng : (58+1).20:2=590
590-410=180
180000:180=1000
Mình chữa câu d tí 9.4576.2 là sai ;;; 9.4567.2 mới đúng
gianroi
Ta có \(\frac{150150150150}{160160160160}=\frac{150150150150:1001001001}{160160160160:1001001001}=\frac{150}{160}=\frac{15}{16}\)
\(\frac{14141414}{15151515}=\frac{14141414:1010101}{15151515:1010101}=\frac{14}{15}\)
Vì \(\frac{15}{16}>\frac{14}{15}=>\frac{150150150150}{160160160160}>\frac{14141414}{15151515}\)
\(\frac{150150150150}{160160160160}=\frac{150.1010101}{160.1010101}=\frac{150}{160}=\frac{15}{16}\)
Ta có:
\(1-\frac{15}{16}=\frac{1}{16}\)
\(1-\frac{14}{15}=\frac{1}{15}\)
\(\frac{1}{16}< \frac{1}{15}\)
\(\Rightarrow\frac{15}{16}>\frac{14}{15}\)
\(\Rightarrow\frac{150150150150}{160160160160}>\frac{14}{15}\)
\(\frac{4-\frac{3}{69}-\frac{168}{117}-\frac{75}{141}}{\frac{5}{69}+\frac{5}{117}+\frac{5}{141}}\)
=\(\frac{\frac{66}{69}-\frac{66}{117}-\frac{66}{141}}{\frac{5}{69}+\frac{5}{117}+\frac{5}{141}}\)
=\(\frac{66\left(\frac{1}{69}+\frac{1}{117}+\frac{1}{141}\right)}{5\left(\frac{1}{69}+\frac{1}{117}+\frac{1}{141}\right)}\)
=\(\frac{66}{5}\)
\(\frac{\frac{2}{5}+\frac{2}{7}+\frac{2}{9}+\frac{2}{11}+\frac{2}{13}}{\frac{3}{5}+\frac{3}{7}+\frac{3}{9}+\frac{3}{11}+\frac{3}{13}}\)+\(\frac{15151515}{45454545}\)=\(\frac{2}{3}\)(\(\frac{\frac{1}{5}+\frac{1}{7}+\frac{1}{9}+\frac{1}{11}+\frac{1}{13}}{\frac{1}{5}+\frac{1}{7}+\frac{1}{9}+\frac{1}{11}+\frac{1}{13}}\))+\(\frac{15.1010101}{45.1010101}\)
=\(\frac{2}{3}\)+\(\frac{15}{45}\)
=\(\frac{2}{3}\)+\(\frac{1}{3}\)=1
1, 69. (-74) - 31 . 74
= (-69) . 74 - 31 . 74
= 74(-69 - 31)
= 74(-100)
= -7400
2, (-2020) . 35 - 2020 . 65
= 2020 . (-35) - 2020 . 65
= 2020(-35 - 65)
= 2020(-100)
= -202000
3, -23 . 59 - 159 . 23
= 23 . (-59) - 159 . 23
= 23(-59 - 159)
= 23 . (-218)
= -5014
4, -147 . 47 + (-47)(-47) - 300
= -147 . 47 + 47 . 47 - 300
= 47(-147 + 47) - 300
= 47 . (-100) - 300
= -4700 - 300
= -5000
5, (-72) . 30 - 31 . (-30) + 3 + 30
= (-72) . 30 + 31 . 30 + 3 + 30
= 30(-72 + 31 + 1) + 3
= 30 . (-40) + 3
= -1200 + 3
= -1197
6, (-82)(-55) + (-82) + (-46)(-82)
= (-82)(-55 + 1 - 46)
= (-82)(-100)
= 8200
7, (-41) . 135 + 135 . (-24) - 35 . (-65)
= 135(-41 - 24) - 35(-65)
= 135(-65) - 35(-65)
= (-65)(135 - 35)
= -65(100)
= -6500
10, 125 . (-88)
= 1000 . \(\frac{1}{8}\) . (-88)
= 1000 . (-11)
= -11000
Câu 8 với 9 mình ko hiểu nên ko giúp bn được
Chúc bạn học tốt!
\(A=\frac{595959}{454545}-\frac{14141414}{15151515}\)
\(A=\frac{595959:10101}{454545:10101}-\frac{14141414:1010101}{15151515:1010101}\)
\(A=\frac{59}{45}-\frac{14}{15}\)
\(A=\frac{59}{45}-\frac{42}{45}=\frac{17}{45}\)
\(B=\frac{65+891+135+909}{731-47+69-253}\)
\(B=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)
\(B=\frac{200+1800}{800-300}=\frac{2000}{500}=4\)
Giải theo cách lớp 5