PT
1
K
Khách
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4 tháng 4 2023
`a,`
`31/23-(7/32+8/23)`
`=31/23-7/32-8/23`
`=(31/23-8/23)-7/32`
`=1-7/32=25/32`
`b,`
`38/45-(8/45-17/51-3/11)`
`=38/45-8/45+17/51+3/11`
`= (38/45-8/45)+17/51+3/11`
`=2/3+17/51+3/11`
`=1+3/11=14/11`
`c,`
`(1/3+12/67+13/41)-(79/67-28/41)`
`= 1/3+12/67+13/41-79/67+28/41`
`= 1/3+(12/67-79/67)+(13/41+28/41)`
`= 1/3+(-1)+1=1/3+(-1+1)=1/3+0=1/3`
`d,`
`1/5+(-1/6)+1/7+(-1/8)+1/9+1/8+(-1/7)+1/6+(-1/5)`
`= (1/5+ -1/5)+(-1/6+1/6)+(1/7+ -1/7)+(-1/8 +1/8)+1/9`
`= 0+0+0+0+1/9=1/9 .`
13 tháng 1 2016
A)(-4)*5+15 H)(-4)*4+5*(-10) O) (-5) * (-3) +(-4)^2
= (-20)+15 = -16 + (-15) = 15 + 16
= -5 = -31 = 31
B)(-32)+(-5) * 7 i)99 * (-5)-11*(-7) F) (-1)^3 +(-2) *(-3)
= (-32) + (-35) =-495 - (-77) = -1 + 6
= -67 = -572 = 5
C)(-5) * 2 + (-6) *4 k) (-4)*2+(-2)+12 Q) (-11) * (-4) - (-8 * 5)
= (-10) + (-24) =4 * (-2) + (-2) +12 = 44 + 40
= -34 = (-2) *(4 +12) = 84
D)119-(-14) *10 = (-2) * 16 S) 100 - (-15) * 2
= 119 + 140 = -72 = 100 + 30
=259 L) (-32) +(-15) * (-3) = 130
E)112+(-11)*4 = (-32)+ 45
=112 + (-40) = 13
=72 M) (-12) *3 + (-6) * 5
G)(-22)+ (-2) *6 = -36 + (-30)
= (-22) + (-12) =-66
= -34 N) 100- (-14) * (-3)
=100 + (-42)
= 58
14 tháng 3 2018
a, A= 1/5.6+1/6.7+1/7.8+...+1/24.25
=1/5-1/6+1/6-1/7+1/7-1/8+...+1/24-1/25
=1/5-1/25
=4/25
hok tốt k nha
NV
8
19 tháng 8 2016
số số hạng là :
( 1000000 - 1 ) : 1 + 1 = 1000000
tổng là :
( 1000000 + 1 ) x 1000000 : 2 = 500000500000
đáp số : 500000500000
NM
2
10 tháng 9 2021
a) \(1+2+3+...+2021=\dfrac{\left(2021+1\right)\left(\dfrac{2021-1}{1}+1\right)}{2}=2043231\)
b) Giống a
c) \(11+13+15+...131=\dfrac{\left(131+11\right)\left(\dfrac{131-11}{2}+1\right)}{2}=4331\)
25 tháng 7 2016
160-(2^3.5^2-6.25)= 160-(8.25-150)=160-50=110
4.5^2-32.2^4= 4.25 - 32.16= 100-512=-412
5871:[928-(247-82).5]=5871:[(928-165).5=5871: ( 763.5)=5871:103=57
777:7+1331:11^3 = 111+1331:1331 = 111+1=112
17.85+15.17-120=17(85+15)-120=17.100-120=1700-120=1580
15.141+59.15=15(141+59)=15.200=3000
20-[30-(5-1)^2]=20-[30-4^2]=20-(30-16)=20-11=9
37-11.3.(24-23)+22.10= 37-33.1+220=37-253=-216
S
25 tháng 7 2016
160-(2^3.5^2-6.25)= 160-(8.25-150)=160-50=110
4.5^2-32.2^4= 4.25 - 32.16= 100-512=-412
5871:[928-(247-82).5]=5871:[(928-165).5=5871: ( 763.5)=5871:103=57
777:7+1331:11^3 = 111+1331:1331 = 111+1=112
17.85+15.17-120=17(85+15)-120=17.100-120=1700-120=1580 15.141+59.15=15(141+59)=15.200=3000
20-[30-(5-1)^2]=20-[30-4^2]=20-(30-16)=20-11=9
37-11.3.(24-23)+22.10= 37-33.1+220=37-253=-216
18 tháng 7 2021
a) Ta có: \(\dfrac{-5}{18}+\dfrac{32}{45}-\dfrac{9}{10}\)
\(=\dfrac{-25}{90}+\dfrac{64}{90}-\dfrac{81}{90}\)
\(=\dfrac{-42}{90}=-\dfrac{7}{15}\)
b) Ta có: \(\left(-\dfrac{1}{4}+\dfrac{51}{33}-\dfrac{5}{3}\right)-\left(-\dfrac{15}{12}+\dfrac{6}{11}-\dfrac{42}{29}\right)\)
\(=\dfrac{-1}{4}+\dfrac{17}{11}-\dfrac{5}{3}+\dfrac{5}{4}-\dfrac{6}{11}+\dfrac{42}{29}\)
\(=\dfrac{-5}{3}+\dfrac{42}{29}\)
\(=\dfrac{-145}{87}+\dfrac{126}{87}=\dfrac{-19}{87}\)
c) Ta có: \(1-\dfrac{1}{2}+2-\dfrac{2}{3}+3-\dfrac{3}{4}+4-\dfrac{1}{4}-3-\dfrac{1}{3}-2-\dfrac{1}{2}-1\)
\(=\left(1-1\right)-\left(\dfrac{1}{2}+\dfrac{1}{2}\right)+\left(2-2\right)-\left(\dfrac{2}{3}+\dfrac{1}{3}\right)+\left(3-3\right)-\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+4\)
\(=-1-1-1+4\)
=1
18 tháng 7 2021
a) Ta có: −518+3245−910−518+3245−910
=−2590+6490−8190=−2590+6490−8190
=−4290=−715=−4290=−715
b) Ta có: (−14+5133−53)−(−1512+611−4229)(−14+5133−53)−(−1512+611−4229)
=−14+1711−53+54−611+4229=−14+1711−53+54−611+4229
=−53+4229=−53+4229
=−14587+12687=−1987=−14587+12687=−1987
c) Ta có: 1−12+2−23+3−34+4−14−3−13−2−12−11−12+2−23+3−34+4−14−3−13−2−12−1
=(1−1)−(12+12)+(2−2)−(23+13)+(3−3)−(34+14)+4=(1−1)−(12+12)+(2−2)−(23+13)+(3−3)−(34+14)+4
=−1−1−1+4=−1−1−1+4
=1
S
1
12 tháng 1 2022
Bài 1:
\(=\dfrac{-3-39}{42}+\dfrac{-6-11}{17}-\dfrac{1}{6}=-\dfrac{119}{48}\)
Bài 2:
=>x:5=-13/20
hay x=-65/20=-13/4
PK
1
H
2 tháng 3 2022
\(\dfrac{1}{6}+\dfrac{-2}{5}=\dfrac{5}{30}+\dfrac{-12}{30}=\dfrac{-7}{30}\)
\(\dfrac{5}{12}-\dfrac{7}{8}=\dfrac{10}{24}-\dfrac{21}{24}=\dfrac{-11}{24}\)
\(\dfrac{-4}{25}:\dfrac{-32}{45}=\dfrac{-4}{25}.\dfrac{-45}{32}=\dfrac{-1}{5}.\dfrac{-9}{8}=\dfrac{4}{40}\)
\(\dfrac{-2}{9}.\dfrac{7}{11}+\dfrac{-2}{9}.\dfrac{10}{11}+\dfrac{-2}{9}.\dfrac{5}{11}=\dfrac{-2}{9}\left(\dfrac{7}{11}+\dfrac{10}{11}+\dfrac{5}{11}\right)=\dfrac{-2}{9}.\dfrac{22}{11}=\dfrac{-2}{9}.2=\dfrac{-4}{9}\)
a) − 5 11 + − 6 11 + 2 = − 5 11 + − 6 11 + 2 = − 1 + 2 = 1
b) − 1 32 + 1 2 + − 15 32 = − 1 32 + − 15 32 + 1 2 = − 1 2 + 1 2 = 0