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a) 42.50 – 38.50 – 25.4 = 50.(42 – 38) – 25.4 = 50.4 – 25.4 = (50 – 25).4 = 25.4 = 100
b) 32.38 + 17.94 – 15.38 – 32.17 = 38.(32 – 15) + (94 – 32).17 = 38.17 + 62.17 = 17.(38+62) = 17.100 = 1700
\(a,=27\cdot20+73\cdot20-27=20\left(27+73\right)-27\\ =20\cdot100-27=2000-27=1973\\ b,=42\cdot50-38\cdot50-50\cdot2=50\left(42-38-2\right)=50\cdot2=100\\ e,=254\left(58+21\cdot2\right)=254\cdot100=25400\\ c,=53\left(12+172-84\right)=53\cdot100=5300\\ d,=24\left(31+42+27\right)=24\cdot100=2400\\ f,=\left(9-8-...-1\right)\left(500\cdot9-500\cdot9\right)=\left(9-8-...-1\right)\cdot0=0\)
\(\left(-79\right).\left(8-313\right)-313.79\)
\(=-79.\left(8-313+313\right)\)
\(=-79.8\)
\(=-632\)
\(32.17.\left(-125\right).25.2\)
\(=32.25.\left(-125\right).2.17\)
\(=800.\left(-250\right).17\)
\(=200000.17\)
\(=3400000\)
học tốt
a, 165:11.999 + 85.999 = (15.11):11.999 + 85.999 = [(15.11):11].999 + 85.999
= 15.(11:11).999 + 85.999 = 15.999 + 85.999 = (15+85).999 = 99900
b, 25.4 + 25:5 – 4.(30 – 5) – 5 = 25.4 + 25:5 – 4.25 – 5 = (25.4 – 4.25) + (25:5 – 5) = 0 + 0 = 0
Bài 3:
a: Ta có: \(23\left(42-x\right)=23\)
\(\Leftrightarrow42-x=1\)
hay x=41
b: Ta có: 15(x-3)=30
nên x-3=2
hay x=5
Bài 1:
a: 32+89+68=100+89=189
b: 64+112+236=300+112=412
c: \(1350+360+650+40=2000+400=2400\)
\(\left(27+55\right)+\left(345-27-55\right)\)
\(=27+55+345-27-55\)
\(=\left(27-27\right)+\left(55-55\right)+345\)
\(=0+0+345\)
\(=345\)
\(38.65+38.50-38.15\)
\(=38.\left(65+50-15\right)\)
\(=38.100\)
\(=3800\)
\(\left(123-60\right)-\left(2017-60+123\right)\)
\(=123-60-2017+60-123\)
\(=\left(123-123\right)-\left(60-60\right)-2017\)
\(=0-0-2017\)
\(=-2017\)
Bỏ dấu ngoặc rồi tính:
(27 + 55 ) + ( 345 - 27 - 55 )
= 27 + 55 + 345 - 27 - 55
= (27-27) + (55-55) + 345
= 0 + 0 + 345
= 345
Tính nhanh:
38.65 + 38.50 - 38.15
= 38.(65+50-15)
= 38.100
= 3800
Bỏ ngoặc rồi tính:
( 123 - 60 ) - ( 2017 - 60 + 123 )
= 123 - 60 - 2017 + 60 - 123
= (123-123) + (60-60) - 2017
= 0 + 0 - 2017
= 0 - 2017
= -2017
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