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\(\left(\frac{10}{99}+\frac{11}{199}-\frac{12}{299}\right)\times\left(\frac{1}{2}-\frac{1}{3}+-\frac{1}{6}\right)\)
\(=\left(\frac{10}{99}+\frac{11}{199}-\frac{12}{299}\right)\times\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(=\left(\frac{10}{99}+\frac{11}{199}-\frac{12}{299}\right)\times\left(\frac{3}{6}-\frac{2}{6}-\frac{1}{6}\right)\)
\(=\left(\frac{10}{99}+\frac{11}{199}-\frac{12}{299}\right)\times0\)
\(=0\)
64.2x-2=22020
26.2x:22=22020
26.2x =22020.22
26.2x =22022
2x =22022:26
2x =22018
21+3.\(|\)x\(|\)=3.(42-1)
21+3.\(|\)x\(|\)=3.15
21+3.\(|\)x\(|\)=45
3.\(|\)x\(|\)=45-21
3.\(|\)x\(|\)=24
\(|\)x\(|\)=24:3
\(|\)x\(|\)=8
\(|\)x\(|\)=\(|\)8;-8\(|\)
=>x\(\in\){8;-8}
Chúc bn học tốt
( 7 . x - 11)\(^3\)=2\(^5\). 2\(^2\)+ 200
( 7 . x - 11)\(^3\)=32 . 4 + 200
( 7. x - 11)\(^3\)=328
( 7 . x - 1331) = 328
7 . x = 328 + 1331
7.x = 1659
x = 1659 : 7
x = 237
(7x-11)3=25.22+200
(7x-11)3=27+200
(7x-11)3=128+200
(7x-11)3=328
vô lí vì \(328\ne?^?\)được
vậy x\(\notin\varnothing\)
\(45-/x+14/=2^3.3\)
\(=>45-/x+14/=24\)
\(TH1:x\ge14=>/x+14/=\left(x+14\right)\)
\(=>45-/x+14/=24\)
\(=>45-\left(x+14\right)=24\)
\(=>x+14=45-24\)
\(=>x=21-14\)
\(=>x=7\)
\(TH2:x< 14=>/x+14/=-\left(x+14\right)=-x-14\)
\(=>45-/x+14/=24\)
\(=>45+x-14=24\)
\(=>45-x=24+14\)
\(=>x=45-38\)
\(=>x=7\)
Vậy...
\(M=1+\dfrac{1}{5}+\dfrac{3}{35}+...+\dfrac{3}{9999}\\ =\dfrac{3}{3}+\dfrac{3}{15}+\dfrac{3}{35}+...+\dfrac{3}{9999}\\ =\dfrac{3}{2}\left(\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+...+\dfrac{2}{99\cdot101}\right)\\ =\dfrac{3}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{99}-\dfrac{1}{101}\right)\\ =\dfrac{3}{2}\left(1-\dfrac{1}{101}\right)=\dfrac{3}{2}\cdot\dfrac{100}{101}=\dfrac{150}{101}\)
255 - 21 . 5 . ( 198 : 11 - 8 )
= 255 - 105 . ( 18 - 8 )
= 255 - 105 . 10
= 255 - 1050
= -795
720 : [ 41 - ( 2 . x . 5 ) ] = 23 . 5
720 : [ 41 - ( 10 . x ) ] = 40
41 - ( 10 . x ) = 720 : 40
41 - ( 10 . x ) = 18
10 . x = 41 - 18
10 . x = 23
x = 23/10