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1. Tính nhanh
a) - (2789 - 435) + (1789 - 1435 )
= - 2789 + 435 + 1789 - 1435
= ( - 2789 + 1789 ) + ( 435 - 1435 )
= (-1000) + (-1000) = - 2000
Vậy : - (2789 - 435) + (1789 - 1435 ) = -2000
b) (-2010)+36.41-36.(-59)+(-2010)
= (-2010) + 36.[ 41 - (-59)] + (-2010)
=(-2010) + 36. 100 + (-2010)
= (-2010) + 3600 + (-2010)
= 1590 + (-2010)
=-420
Vậy : (-2010)+36.41-36.(-59)+(-2010) = -420
P/s : Hình như đề bài sai ( câu b)
a) - (2789 - 435) + (1789 - 1435 )
= - 2789 + 435 + 1789 - 1435
= ( - 2789 + 1789 ) + ( 435 - 1435 )
= (-1000) + (-1000)
= - 2000
A)
-(2789-435)+(1789-1435)
= -(2000+789-435)+(1000+789-1000-435)
= -2000-789+435+1000+789-1000-435
= -2000 +(789-789)+ (1000-1000) +(435-435)
= -2000
B)
-(-2010)+36.41-36.(-59)+(-2010)
= 2010 +36. (41+59)- 2010
= (2010-2010) +36. 100
= 3600
C)
-75.(18-65)-65.(75-18)
= -75.18+75.65-65.75+65.18
=18. (-75+65)
= 18. (-10)
= -180
\(\left(-75\right)\left(18-65\right)-65\left(75-18\right)\)
\(=\left(-75\right).18-\left(-75\right).65-65.75+65.18\)
\(=\left(-75\right).18+75.65-65.75+65.18\)
\(=18.\left[\left(-75\right)+65\right]+\left(75.65-65.75\right)\)
\(=18.\left(-10\right)=-180\)
P/s: Hoq chắc
a) =-(-2010)+(-2010)+36*54-36*(-59)=2010+(-2010)+ 36*(54-59)=0+36*5=.....
b
\(\text{- ( 2789 _ 435 ) + ( 1789 _ 1435 )}\)
\(=-2789+435+1789-1435\)
\(=\left(-2789+1789\right)+\left(435-1435\right)\)
\(=-1000+-1000\)
\(=-2000\)
\(=-\left(-2010\right)+36.41-36.\left(-59\right)\)
\(=2010+36.\left(41+59\right)\)
\(=2010+36.100\)
\(=2010+3600\)
\(=5610\)
\(-75.\left(18-65\right)-65.\left(75-18\right)\)
\(=-75.18+75.65-65.75+65.18\)
\(=18.\left(-75+65\right)+75.\left(65-65\right)\)
\(=18.\left(-10\right)+75.0\)
\(=-180\)
\(-15:x=3\)
\(x=-15:3\)
\(x=-5\)
\(-3x+8=7\)
\(-3x=-1\)
\(x=\frac{1}{3}\)
\(\left(x-6\right).\left(7-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-6=0\\7-x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=6\\x=7\end{cases}}}\)
\(\Rightarrow x\in\left\{6;7\right\}\)
\(2.\left(x-3\right)-3.\left(x-5\right)=4.\left(3-x\right)-18\)
\(2x-6-3x+15=12-4x-18\)
\(2x-3x+4x=12-18-15+6\)
\(3x=-15\)
\(\Rightarrow x=-5\)
\(-a.\left(c-d\right)-d.\left(a+c\right)=-c.\left(a+d\right)\)
\(-a.c+a.d-d.a+-d.c=-c.\left(a+d\right)\)
\(-c.\left(a+d\right)+a.\left(d-d\right)=-c.\left(a+d\right)\)
\(-c.\left(a+d\right)+a.0=-c.\left(a+d\right)\)
\(\Rightarrow-c.\left(a+d\right)=-c.\left(a+d\right)\)
(3a+2).(2a–1)+(3–a).(6a+2)–17.(a–1)
=6a²−3a+4a−2+18a+6−6a²−2a−17a+17
=(6a²−6a²)+(−3a+4a+18a−2a−17a)+(17−2+6)
=0+0+21
=21
học tốt
-(-2010) +36.41 - 36. (-59) + (-2010)
= 2010 + 1476 -2124 -2010
= (2010-2010) + (1476-2124)
= -648
-75.(18-65)-65.(75-18)
= -75. (-47) - 65. 57
= 3525 - 3705
= -180
a, = -2789 + 435 + 1789 - 1435
= (-2789+1789)+(435-1435)
= -1000-1000
=-2000
b, = (2010-2010)+36(41+59)
=36.100
=3600
\(\text{-75.(18-65)-65.(75-18)}\)
\(=-75.18+75.65-65.75+65.18\)
\(=\left(-75+65\right).18+75.\left(65-65\right)\)
\(=-10.18+75.0\)
\(=-180\)
học tốt
-75.(18-65)-65.(75-18)
= −75.18 + 75.65 − 65.75 + 65.18
= −75 + 65 .18 + 75. 65 − 65
= −10.18 + 75.0
= −180
Bài 1:
a) (-15)+(-122)=-15-122=-137
b) 17-25+55-17=17-17-25+55=0-25+55=30
c)(-5).8.(-2).3=-40.(-6)=240
d) |-127|-18.(5-6)=127-18.40=127-720=-593
Bài 2:
a) 25-(-75)+32-(32+75)=25+75+32-32-75=25
b) 210+[46+(-210)+(-26)]=210+46-210-26=20
g) -(2789-435)+(1789-1435)=-2789+435+1789-1435=-2000
h) (-18)+(-31)+98+|-18|+(-69)=-18-31+98+18-69=-2
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b) -(-2010)+36.41-36.(-59)+(-2010)
= 2010+36(41+59)+(-2010)
= (2010+-2010)+36.100
=0+3600=3600
a) - (2789 - 435) + (1789 - 1435 )
= - 2789 + 435 + 1789 - 1435
= ( - 2789 + 1789 ) + ( 435 - 1435 )
= (-1000) + (-1000) = - 2000
Vậy : - (2789 - 435) + (1789 - 1435 ) = -2000