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1234x5678x(630-315x2):1996
Chú ý 630-315x2=630-630=0
=>1234x5678x(630-315x2):1996=0
(1+2+4+8+...+512)x(101x102-101x101-50-51)
Xét thừa số thứ 2
101x102-101x101-50-51
=101x(102-101)-(50-51)
=101x1-101
=101-101
=0
Vậy (1+2+4+8+...+512)x(101x102-101x101-50-51)=0
(1-1/2) x (1-1/3) x .... x (1-1/100)
= 1/2 x 2/3 x ... x 99/100
= 1x2x...x99/2x3x..x100
= 1/ 100
a, \(\frac{3}{5}+25-\frac{1}{5}\)
\(=\left(\frac{3}{5}-\frac{1}{5}\right)+25\)
\(=\frac{2}{5}+25\)
\(=25\frac{2}{5}\)
\(=25,4\)
b, \(13.3.32,27+67,63.39\)
\(=39.32,27+67,63.39\)
\(=39\left(32,37+67,63\right)\)
\(=39.100\)
\(=3900\)
c, \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)....\left(1-\frac{1}{100}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}......\frac{99}{100}\)
\(=\frac{1}{100}\)
2+3/4=11/4 ; 2-3/5=7/5
5/7:6=5/42 ; 5+2/7=37/7
Bài 2: a) x-1/6=1/2+1/3
x-1/6=5/6
x=5/6+1/6
x=1
b) x+1/8=1/2-1/3
x+1/8=1/6
x=1/6-1/8
x=1/24
c) x:1/2=2/3.3/4
x:1/2=1/2
x=1/2.1/2
x =1/4
1234 x 5678 x ( 630 - 315 x 2) : 2020
= 1234 x 5678 x (630 -630 ) : 2020
= 1234 x5678 x 0 : 2020
= 0
Ta có:
+) 10/20 : 1/6% + 69%
= 10/20 x 6%/1 + 69%
= \(\frac{10}{20}\text{x}\frac{6}{100}+\frac{69}{100}\)
=\(\frac{3}{100}+\frac{69}{100}\)
=\(\frac{72}{100}\)= 0,72
+) \(\frac{20}{2}:100\%\text{x}6:100\text{x}89\%\)
=\(\frac{20}{2}\text{x}6\text{x}89\%:\left(100\%\text{x}100\right)\)
=\(\frac{20}{2}\text{x}6\text{x}\frac{89}{100}:100\)
=\(\frac{20\text{x}6\text{x}89}{2\text{x}100\text{x}100}\)
=\(\frac{3\text{x}89}{5x100}\)
=\(\frac{267}{500}\)
=0.534
ủng hộ mik nhé
\(\frac{10}{20}:\frac{1}{6}\%+69\%=300,69\)
\(\frac{20}{2}:100\%x6:100x89\%=0,534\)
Phần A hình như sai đầu bài , mình sửa lại và làm luôn nhé :
A = ( 2 + 4 + 6 + 8 .... + 100 ) x ( 142142 x 143 - 143143 x 142 )
A = ( 2 + 4 + 6 + 8 + ... + 100 ) x ( 142 x 1001 x 143 - 143 x 1001 x 142 )
A = ( 2 + 4 + 6 + 8 + .. + 100 ) x 0
A = 0
B = ( 630 - 315 x 2 ) : ( 1 + 2 + 3 + ... + 1000 )
B = ( 630 - 630 ) : ( 1 + 2 + 3 + ... + 100 )
B = 0 : ( 1 + 2 + 3 + ... + 100 )
B = 0