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Tìm x
a,\(\frac{5}{4}x=\frac{2}{3}-1,5=\frac{2}{3}-\frac{3}{2}=\frac{4}{6}-\frac{9}{6}=\frac{-5}{6}\)
\(x=\frac{-5}{6}:\frac{5}{4}=\frac{-5}{6}.\frac{4}{5}=\frac{5.\left(-1\right).2.2}{2.3.5}=\frac{-2}{3}\)
b, \(\frac{2}{7}x-\frac{3}{2}x=\frac{-21}{4}.\frac{2}{7}=\frac{-3}{2}\)
\(x.\left(\frac{2}{7}-\frac{3}{2}\right)=\frac{-3}{2}\)
\(x.\frac{-17}{14}=\frac{-3}{2}\)
\(x=\frac{-3}{2}:\frac{-17}{14}=\frac{-3}{2}.\frac{14}{-17}=\frac{21}{17}\)
Bài 1 d)
\(1-2+3-4+5-6+...+2013\)
\(=1+\left(-2+3\right)+\left(-4+5\right)+...+\left(-2012+2013\right)\)
\(=1+1+1+...+1\left(1006s\right)\)
\(=1006.1=1006\)
\(A=\left(25^6+15^6-10^6\right)\div5^6\)
\(A=\left(25+15-10\right)^6\div\left(5^6\right)\)
\(A=30^6\div5^6\)
\(A=\left(30\div5\right)^6\)
\(A=6^6\)
1:
a: \(=\dfrac{-4}{7}+\dfrac{4}{7}+\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=-\dfrac{1247}{1190}\)
b:
Sửa đề: \(\dfrac{-5}{13}+\dfrac{4}{19}+\dfrac{-8}{13}+\dfrac{15}{19}+\dfrac{45}{6}\)
\(=\dfrac{-5}{13}-\dfrac{8}{13}+\dfrac{4}{19}+\dfrac{15}{19}+\dfrac{45}{6}=\dfrac{9}{2}\)
\(a,12-\left(4+105-13\right)+\left(4+105-3\right)\)
\(=12-4-105+13+4+105-3\)
\(=12+\left(-4+4\right)+\left(-105+105\right)+\left(13-3\right)\)
\(=12+0+0+10\)
\(=22\)
\(b,-15+\left(-17+21-35\right)+\left(4+105-13\right)\)
\(=-15-17+21-35+4+105-13\)
\(=\left(-15-35\right)+\left(-17-13\right)+\left(21+4+105\right)\)
\(=-50-30+130\)
\(=-50+100\)
\(=50\)
\(c,\left(\left|-5\right|+\left|+7\right|+\left|-9\right|\right)-\left(\left|+5\right|+\left|-7\right|+9\right)\)
\(=\left(5+7+9\right)-\left(5+7+9\right)\)
\(=0\)
giải:-25.15+35.70-55.25
=25.(-15)+35.70-55.25
=25(-15-55)+35.70
=25.(-70)+35.70
=-25.70+35.70
=70.(-25+35)
=70.10
=700
mn giúp mik vơi mn:((
\(=\left(\frac{12}{19}.\frac{19}{12}\right).\left(-\frac{13}{17}.\frac{17}{13}\right).\frac{7}{15}\)
\(=1.-1.\frac{7}{15}\)
\(=-1.\frac{7}{15}\)
\(=-\frac{7}{15}\)