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=\(\frac{2^52^2x3^4}{3^3x2^5}\)=\(\frac{2^23^33}{3^3}\)=4.3=12
b, Ta có : \(\frac{2^7x9^2}{3^3x2^5}=\frac{2^52^2x3^23.3}{3.3^2x2^5}=\frac{2^2x3}{x}=12\)
(1/2-2/3)-(5/3-3/2)+(7/3-5/2)
=1/2-2/3-5/3+3/2+7/3-5/2
=(1/2+3/2-5/2)-(2/3+5/3-7/3)
=-1/2-0=-1/2
\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
\(=3-\frac{1}{4}+\frac{2}{3}-5+\frac{1}{3}+\frac{6}{5}-6+\frac{7}{4}-\frac{3}{2}\)
\(=\left(3-5-6\right)+\left(\frac{-1}{4}+\frac{7}{4}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)+\left(\frac{6}{5}-\frac{3}{2}\right)\)
\(=\left(-8\right)+2+1+\frac{-3}{10}\)
\(=\left(-5\right)+\frac{-3}{10}=\frac{-53}{10}=-5,3\)
(3-1/4+2/3)-(5-1/3-6/5)-(6-7/4+3/2)
=3-1/4+2/3-5-1/3-6/5-6-7/4+3/2
=(3-5-6)+(-1/4-7/4)+(2/3-1/3)+(6/5/3/2
=(-8)+2+1+(-3/10)
=(-5)+(-3/10)=-53/10=-5,3
\(12.\left(-\frac{2}{3}\right)+\frac{4}{3}\)
\(=-8+\frac{4}{3}\)
\(=\frac{-20}{3}\)
\(\frac{4}{5}.\left(\frac{7}{2}+\frac{1}{4}\right)^2\)
\(=\frac{4}{5}.\left(\frac{15}{4}\right)^2\)
\(=\frac{4}{5}.\frac{225}{16}\)
\(=\frac{45}{4}\)
\(12.\left(-\frac{2}{3}\right)+\frac{4}{3}\)
\(=-8+\frac{4}{3}=-\frac{20}{3}\)( bấm máy tính ... số cx ko to lắm nên cx hợp lí :v)
\(\frac{4}{5}.\left(\frac{7}{2}+\frac{1}{4}\right)^2\)
\(=\frac{4}{5}.\left(\frac{14}{4}+\frac{1}{4}\right)^2\)
\(=\frac{4}{5}.\left(\frac{15}{4}\right)^2\)
\(=\frac{4}{5}.\frac{225}{16}\)
rút gọn ta đc \(=\frac{45}{4}\)
ta có \(2^7.9^2:3^3.2^5\)
=\(2^7.3^4:3^2.2^5\)
=\(\left(2^7.2^5\right):\left(3^4.3^3\right)\)
=\(2^{12}:3^7\)
=\(4096:2187\)=\(1,872885231\approx2\)