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24 tháng 6 2017

\(I=10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3\cdot7\cdot11\cdot13\cdot37}\right)\)

\(=10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)

\(=10101\cdot\dfrac{1}{31746}\)

\(=7\cdot\dfrac{1}{22}\)

\(=\dfrac{7}{22}\)

24 tháng 6 2017

\(I=10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)

\(I=10101.\left(\dfrac{5}{111111}+\dfrac{1}{2}.\dfrac{5}{111111}-\dfrac{5}{111111}.\dfrac{4}{5}\right)\)

\(I=10101.\dfrac{5}{111111}.\left(1+\dfrac{1}{2}-\dfrac{4}{5}\right)\)

\(I=\dfrac{5}{11}.\dfrac{7}{10}=\dfrac{7}{22}\)

Chúc bạn học tốt!!!

31 tháng 3 2017

\(10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3\cdot7\cdot11\cdot13\cdot37}\right)\)=\(10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)

= \(10101\cdot\left(\dfrac{5}{111111}-\dfrac{4}{111111}+\dfrac{5}{222222}\right)\)

= \(10101\cdot\left(\dfrac{1}{111111}+\dfrac{5}{222222}\right)\)

= \(10101\cdot\left(\dfrac{2}{222222}+\dfrac{5}{222222}\right)\)

= \(10101\cdot\dfrac{7}{222222}\)

= \(\dfrac{10101\cdot7}{222222}=\dfrac{10101\cdot7}{10101\cdot22}=\dfrac{7}{22}\)

1 tháng 4 2017

10101.(\(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\))

= 10101.(\(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\))

= 10101.(\(\dfrac{1}{111111}+\dfrac{5}{222222}\))

= 10101. \(\dfrac{7}{222222}\)

= \(\dfrac{10101.7}{222222}\)= \(\dfrac{70707}{22222}\)=\(\dfrac{7}{22}\)

Chúc pạn hok tốt!!!!!!!

6 tháng 7 2017

\(10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)

\(=10101.\dfrac{5}{111111}+10101.\dfrac{5}{222222}-10101.\dfrac{4}{3.7.11.13.37}\)

\(=\dfrac{5}{11}+\dfrac{5}{22}-\dfrac{4}{11}\)

\(=\dfrac{7}{22}\)

18 tháng 5 2017

\(M=\dfrac{120-\dfrac{1}{2}.40.5.\dfrac{1}{5}.20.\dfrac{1}{4}-20}{1+5+....+41}\\ =\dfrac{120-20.5-20}{1+5+...+41}\\ =\dfrac{0}{1+5+...+41}\\ =0\)

\(N=10101\left(\dfrac{6}{3.7.11.13.37}+\dfrac{6}{2.3.7.11.13.37}-\dfrac{7}{3.7.11.13.37}\right)\\ =10101\left(-\dfrac{2}{2.3.7.11.13.37}+\dfrac{6}{2.3.7.11.13.37}\right)\\ =3.7.13.37\left(\dfrac{4}{2.3.7.11.13.37}\right)=\dfrac{4}{2.11}=\dfrac{2}{11}\)

21 tháng 5 2017

giỏi z đạt - thánh toán học

31 tháng 7 2017

Trời ơi cái đề bài !!!

Thoy thì làm từng câu vậy

a) \(I=10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)

\(I=10101.\left(\dfrac{10}{222222}+\dfrac{5}{222222}-\dfrac{8}{222222}\right)\)

\(I=10101.\left(\dfrac{15}{222222}-\dfrac{8}{222222}\right)\)

\(I=10101.\dfrac{7}{222222}\)

\(I=\dfrac{7}{22}\)

31 tháng 7 2017

1.

a) \(A=10101\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)\(A=\dfrac{10101.5}{10101.11}+\dfrac{10101.5}{10101.22}-\dfrac{10101.4}{10101.11}\)

\(A=\dfrac{5}{11}+\dfrac{5}{22}-\dfrac{4}{11}=\dfrac{7}{22}\)

14 tháng 4 2018

A=7/22

Ai thấy đúng thì k cho mik nha

14 tháng 4 2018

A=6/11 bạn ơi

10 tháng 4 2016

=\(10101.\left(\frac{5}{111111}+\frac{5}{222222}.\frac{4}{111111}\right)\)

=\(10101.\left(\frac{5}{111111}+\frac{20}{24691308642}\right)\)

=\(10101.\frac{1111130}{24691308642}\)

=0,4545........