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\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(A=3,1-2,5+2,5-3,1\)
\(A=\left(3,1-3,1\right)-\left(2,5-2,5\right)\)
\(A=0-0\)
\(A=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(B=5,3-2,8-4-5,3\)
\(B=\left(5,3-5,3\right)-\left(2,8+4\right)\\ B=0-6,8\\ B=-6,8\)
A= (3,1 - 2,5) - (-2,5 + 3,1)
=3.1-2.5+2.5-3.1
=0
B= (5,3 - 2,8) - (4 + 5,3)
=5.3 - 2.8-4-5.3
= -6.8
C= -(251.3 + 281) + 3.251 - (1-281)
=-251.3-281+3.251-1+281
=-1
D= -(3/5+3/4)−(−3/4+2/5)
= -3/5-3/4+3/4-2/5
= -5/5
=-1
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)=3,1-2,5+2,5-3,1=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)=5,3-2,8-4-5,3=-6,8\)
\(C=-\left(215\cdot3+281\right)+3\cdot215-\left(1-281\right)=-215\cdot3-281+3\cdot215-1+281=1\)
\(D=-\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)=-\frac{3}{5}-\frac{3}{4}+\frac{3}{4}-\frac{2}{5}=-1\)
A = \(\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(=3,1-2,5+2,5-3,1=6,2\)
B = \(\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=5,3-2,8-4-5,3=-6,8\)
C = \(-\left(251.3+281\right)+3.251-\left(1-281\right)\)
\(=-251.3-281+3.251-1+281=-1\)
D = \(-\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)\)
\(=-\frac{3}{5}-\frac{3}{4}+\frac{3}{4}-\frac{2}{5}=-1\)
(Nhớ k cho mình với nhá!)
1a, (-3,8) + [ (-5,7)+3,8]
= (-3,8+3,8) -5,7
= -5,7
b, 31,4 +[6,4 +(-18)]
= 31,4 - 11,6
= 19,8
c,[(9,6 )+4,5 ] +[9,6 +(-1,5)]
= 9,6 +9,6 +(4,5-1,5)
= 19,2 +3
=22,2
d, [ (-4,9) + (-7,8)] +[1,9+2,8]
= (-4,9 +1,9)+ (-7,8+2,8)
= -3 -5
=-8
e, (3,1-2,5)-(-2,5+3,1)
= (3,1-3,1)+(2,5-2,5)
=0
f, (5,3 -2,8 )- (4+5,3)
= (5,3-5,3) -2,8-4
= -6,8
g, -(251,3 +281 )+ 3,251 -(1-281)
= -251,3-281+3,251 -1+281
= (-281+281) -251,3 +3,251 -1
= -249,049
h,-(3/54+3/4)-(-3/4 +2/5)
= -3/54-3/4 +3/4 +2/5
=(-3/4+3/4) -3/54 +2/5
=123/270
chúc bạn học tốt
Bài 5 :
a, ( -4,8 ) + \(\left[\left(-5,7\right)+\left(4,8\right)\right]\)
= (-4,8) + ( 4,8 ) + ( -5,7 )
= (-5,7 )
b) [(-9,6) + (+1,5)] + [(+9,6) + (-1,5)]
= (-9,6 ) + 9,6 + 1,5 + ( -1,5 )
= 0
c) (3,1 - 2,5) - (-2,5 + 3,1)
= 3,1 - 2,5 + 2,5 - 3,1
= 3,1 -3,1 -2,5 + 2,5
=0
= 3,1 - 2,5 + 2,5 + 3,1
= ( 3,1 - 3,1 ) + ( -2,5 - 2,5 )
= 0
d) 2,7 - (-4,3) + (-8,5) - (-0,6)
= 2,7 + 4,3 - 7 ,9
= 7 - 7,9
= -0,9
d) 2,7 - (-4,3) + (-8,5) - (-0,6)
= 2,7 + 4,3 + 8,5 + 0,6
= 7 + 9,1
= 16,1
e, - \(\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(\dfrac{3}{4}+\dfrac{2}{5}\right)\)
= \(\dfrac{-3}{5}+\dfrac{3}{4}-\dfrac{3}{4}-\dfrac{2}{5}\)
= \(\dfrac{-3}{5}-\dfrac{2}{5}+\dfrac{3}{4}-\dfrac{3}{4}\)
= -1
f) [(-4,9) + (-37,8)] + [(+1,9) + (+2,8)]
= - 4,9 - 37,8 + 1,9 + 2,8
= ( -4,9 + 1,9 ) + ( -37,8 + 2,8 )
= -3 + (-35)
= -38
g) (-4,1) + (-13,7) + (+31) + (-5,9) + (-6,3)
= (-4,1) + ( -5,9 ) + ( -13,7 ) + ( -6,3) + 31
= - 10 - 20 + 31
= 1
h) (-6,5) . 2,8 + 2,8 . (-3,5)
= 2,8 . [ -6,5 - 3,5 ]
= 2,8 . (-10 )
= - 28
a: 3,26-1,549=1,711
b: 0,167-2,396=-2,229
c: -3,29-0,867=-4,157
d: -6,09-3,65=-9,74
e: \(\left(-2.5\right)\cdot\left(-4\right)=2.5\cdot4=10\)
f: \(=\left[\left(-2.5\right)\cdot\left(-4\right)\right]\cdot\left(-7\right)=-7\cdot10=-70\)
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(=3,1-2,5+2,5-3,1=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=5,3-2,8-4-5,3=-6,8\)
\(C=-\left(251.3+281\right)+3.215-\left(1-281\right)\)
\(=-753-281+645-1+281\)
\(=-753+654-1=-100\)
\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(\dfrac{-3}{4}+\dfrac{2}{5}\right)\)
\(=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}=\dfrac{-3}{5}-\dfrac{2}{5}=-1\)
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(=3,1-2,5+2,5-3,1\)
\(=\left(3,1-3,1\right)-\left(2,5-2,5\right)\)
\(=0\)
Vậy \(A=0.\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=5,3-2,8-4-5,3\)
\(=\left(5,3-5,3\right)-\left(2,8+4\right)\)
\(=-\dfrac{34}{5}\)
Vậy \(B=\dfrac{-34}{5}.\)
\(C=-\left(251.3+281\right)+3.215-\left(1-281\right)\)
\(=-251.3-281+3.215-1+281\)
\(=-753-\left(281-281\right)+645\)
\(=-753+645=-108\)
Vậy \(C=-108.\)
\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\)
\(=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}\)
\(=\left(\dfrac{-3}{5}-\dfrac{2}{5}\right)-\left(\dfrac{3}{4}-\dfrac{3}{4}\right)\)
\(=-1\)
Vậy D = -1.