Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Gọi A là biểu thức ta có:
A = 1.2+2.3+3.4+......+99.100
Gấp A lên 3 lần ta có:
A . 3 = 1.2.3 + 2.3.3 + 3.4.3 + … + 99.100.3
A . 3 = 1.2.3 + 2.3.(4 - 1) + 3.4.( 5 - 2) + … + 99.100. (101 - 98)
A . 3 = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + … + 99.100.101 - 98.99.100
A . 3 = 99.100.101
A = 99.100.101 : 3
A = 33.100.101
A = 333 300
\(A=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+...+\frac{1}{49\cdot50}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{49}-\frac{1}{50}\)
\(A=1-\frac{1}{50}\)
\(A=\frac{49}{50}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{49}-\frac{1}{50}\)
\(A=1-\frac{1}{50}\)
\(A=\frac{49}{50}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}< 1\)
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}\)
\(=\frac{99}{100}< 1\)
\(3S=2.3.3+3.4.3+4.5.3+...+19.20.3\)
\(3S=2.3.\left(4-1\right)+3.4.\left(5-2\right)+4.5.\left(6-3\right)+...+19.20.\left(21-18\right)\)
\(3S=2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+19.20.21-18.19.20\)
\(3S=19.20.21-1.2.3\Rightarrow S=\frac{19.20.21-1.2.3}{3}=7.19.20-2\)
A=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\)
A=1-\(\frac{1}{10}\)
A=\(\frac{9}{10}\)
\(\frac{1}{1.2}.\frac{1}{2.3}....\frac{1}{9.10}=\frac{1.1.1.1.1.1}{1.2.2.3.3....9.9.10}=\frac{1}{1.4.9.16.25.36....100}=\frac{1}{13168189440000}\)
b=12+22+32+............+982
b=1.(2-1)+2.(3-1)+3.(4-1)+..............+98.(99-1)
b=1.2-1+2.3-2+3.4-3+.............+98.99-98
b=(1.2+2.3+3.4+..................+98.99)-(1+2+3+............+98)
a-b=1+2+3+...............+98
a-b=\(\frac{98.\left(98+1\right)}{2}\)
a-b=4851
Vậy A-B=4851