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Câu 1:
a. 3/4+1/8=6/8+1/8=7/8
x-5/7=3/5*1/2
x-5/7=3/10
x=3/10+5/7
x=61/70
b.4/5+3/10=8/10+3/10=11/10
x*2/3=8/8+3/4
x*2/3=7/4
x=7/4:2/3
x=21/8
Thế nha, bài này dài đó!!!! :))))
Bài 7:
Số phần kẹo Hùng đã cho Hà và Hồng là:
\(\dfrac{2}{7}+\dfrac{1}{7}=\dfrac{3}{7}\left(phần\right)\)
Hùng còn lại số phần của gói kẹo là:
\(\dfrac{6}{7}-\dfrac{3}{7}=\dfrac{3}{7}\left(phần\right)\)
1:
2 3/4
5 6/5
3 3/9
7 6/8
2:
1/3 + 2/3 + (3/4 + 1/4) = 2
=2
= 4 5/10
\(\dfrac{4}{5}+\dfrac{5}{4}=\dfrac{5}{20}+\dfrac{4}{20}=\dfrac{9}{20}\)
\(\dfrac{3}{4}+\dfrac{7}{8}=\dfrac{18}{24}+\dfrac{21}{24}=\dfrac{39}{24}\)
\(\dfrac{2}{3}+\dfrac{1}{4}=\dfrac{8}{12}+\dfrac{3}{12}=\dfrac{11}{12}\)
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
= 51/20
----------------------------------
= 3/14
------------------------------------
= 4/7 - 2/7
= 2/7
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= 17/45
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= 2/3
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= 2 x 1/4
= 1/2
A = 4\(\dfrac{1}{3}\) + 3\(\dfrac{3}{4}\) + 2 - \(\dfrac{2}{5}\) + 8 - \(\dfrac{3}{5}\) + 7 - \(\dfrac{1}{4}\) + 6 - \(\dfrac{2}{3}\)
A = \(\dfrac{13}{3}\) + \(\dfrac{15}{4}\) + ( 2 + 8 + 6 + 7) - ( \(\dfrac{2}{5}\) + \(\dfrac{3}{5}\)) - \(\dfrac{1}{4}\) - \(\dfrac{2}{3}\)
A = \(\dfrac{13}{3}\) + \(\dfrac{15}{4}\) + 23 - 1 - \(\dfrac{1}{4}\) - \(\dfrac{2}{3}\)
A = ( \(\dfrac{13}{3}\) - \(\dfrac{2}{3}\)) + 22 +( \(\dfrac{15}{4}\) - \(\dfrac{1}{4}\) )
A = \(\dfrac{11}{3}\) + 22 + \(\dfrac{14}{4}\)
A = \(\dfrac{11}{3}\) + 22 + \(\dfrac{7}{2}\)
A = \(\dfrac{22}{6}\) + \(\dfrac{132}{6}\) + \(\dfrac{21}{6}\)
A = \(\dfrac{175}{6}\)
\(\dfrac{4}{5}+\dfrac{5}{4}=\dfrac{16}{20}+\dfrac{15}{20}=\dfrac{21}{20}\)
\(\dfrac{3}{4}+\dfrac{7}{8}=\dfrac{6}{8}+\dfrac{7}{8}=\dfrac{13}{18}\)
\(\dfrac{2}{3}+\dfrac{1}{4}=\dfrac{8}{12}+\dfrac{3}{12}=\dfrac{11}{12}\)