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\(a,347\cdot2^2-2^2\cdot\left(216+184\right):8\)
\(< =>1388-4\cdot400:8\)
\(< =>1388-1600:8\)
\(< =>1388-200\)
\(< =>1188\)
\(b,132-\left[116-\left(132-128\right)^2\right]\)
\(< =>132-\left[116-\left(4^2\right)\right]\)
\(< =>132-100\)
\(< =>32\)
\(c,\left[184:\left(96-124:31\right)-2\right]\cdot3651\)
\(< =>\left[184:\left(96-4\right)-2\right]\cdot3651\)
\(< =>\left[184:92-2\right]\cdot3651\)
\(< =>\left[2-2\right]\cdot3651\)
\(< =>0\cdot3651\)
\(< =>0\)
\(e,\left(2+4+6+8+...+2020\right)\cdot\left(36\cdot333-108\cdot111\right)\)
\(< =>\left[\left(2020-2\right):2+1\right]\cdot\left(36\cdot333-108\cdot111\right)\)
\(< =>1010\cdot\left(11988-11988\right)\)
\(< =>1010\cdot0\)
\(< =>0\)
\(g,1024:2^4+140:\left(38+2^5\right)-7^{23}:7^{21}\)
\(< =>64+140:70-49\)
\(< =>64+2-49\)
\(< =>66-49\)
\(< =>17\)
\(h,\left(44\cdot52\cdot60\right):\left(11\cdot13\cdot15\right)\)
\(< =>137280:2145\)
\(< =>64\)
\(j,\left(2^{17}+15^4\right)\cdot\left(3^{19}-2^{17}\right)\cdot\left(2^4-4^2\right)\)
\(< =>\left(131072+50625\right)\cdot\left(1162261467-131072\right)\cdot\left(16-16\right)\)
\(< =>181697\cdot1162130395\cdot0\)
\(< =>0\)
mk chuc ban hoc tot nhe :))
a: \(=347\cdot4\cdot9\cdot400:8=347\cdot36\cdot50=624600\)
c: \(=16:\left\{400:\left[200-37-138\right]\right\}\)
\(=16:\left\{400:25\right\}=16:16=1\)
e: \(=46-\left[300:15\right]-2=46-20-2=24\)
a )
\(\Rightarrow\frac{x-100}{24}-1+\frac{x-98}{26}-1+\frac{x-96}{26}-1=0\)
\(\frac{x-124}{24}+\frac{x-124}{26}+\frac{x-124}{28}=0\)
\(\left(x-124\right)\left(\frac{1}{26}+\frac{1}{24}+\frac{1}{28}\right)=0\)
\(\Rightarrow x-124=0\Rightarrow x=124\)
\(\frac{14^{16}\cdot21^{31}\cdot35^{48}}{10^{16}\cdot15^{32}\cdot7^{96}}\)
\(=\frac{\left(2\cdot7\right)^{16}\cdot\left(3\cdot7\right)^{31}\cdot\left(5\cdot7\right)^{48}}{\left(2\cdot5\right)^{16}\cdot\left(3\cdot5\right)^{32}\cdot\left(7^2\right)^{48}}\)
\(=\frac{2^{16}\times3^{31}\times5^{48}\times7^{95}}{2^{16}\times3^{32}\times5^{48}\times7^{96}}\)
\(=\frac{1\times1}{3\times7}\)
\(=\frac{1}{21}\)
a: 3x=2y
nên x/2=y/3
Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:
\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{x-y}{2-3}=\dfrac{1}{-1}=-1\)
Do đó: x=-2; y=-3
\(A=\left(-2\right)^3+12\cdot\left(-2\right)^2\cdot\left(-3\right)+48\cdot\left(-2\right)\cdot\left(-3\right)^2-64\cdot\left(-3\right)^3\)
\(=-8+12\cdot4\cdot\left(-3\right)-96\cdot9-64\cdot\left(-27\right)\)
\(=712\)
b: 6a=5b
nên a/5=b/6
Đặt a/5=b/6=k
=>a=5k; b=6k
\(B=\dfrac{2a-3b}{3b-2a}=-1\)
d: \(\left|x-2\right|+\left(y-1\right)^2=0\)
=>x-2=0 và y-1=0
=>x=2 và y=1
\(D=\left|2-2\right|+\dfrac{2-1}{2-1}=0+1=1\)
\(_{\left(184:\left(96-124-31\right)-2\right)\times3651}\)
=(184:(-59)-2)\(\times\)3651
=-5.118644068\(\times\)3651
=-18688.16949