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\(-\frac{2}{3}.\left|-\frac{1}{2}x-\frac{1}{3}\right|=0\)
\(\Rightarrow\left|-\frac{1}{2}x-\frac{1}{3}\right|=0\)
\(\Rightarrow-\frac{1}{2}x-\frac{1}{3}=0\)
\(\Rightarrow-\frac{1}{2}x=\frac{1}{3}\)
\(\Rightarrow x=-\frac{2}{3}\)
1)
a)
\(\frac{-5}{6}.\frac{120}{25}< x< \frac{-7}{15}.\frac{9}{14}\)
\(\frac{-1}{1}.\frac{20}{5}< x< \frac{-1}{5}.\frac{3}{2}\)
\(\frac{-20}{5}< x< \frac{-3}{10}\)
\(\frac{-40}{10}< x< \frac{-3}{10}\)
\(\Rightarrow Z\in\left\{-4;-5;-6;-7;-8;-9;-10;...;-39\right\}\)
\(a)x+30\%x=-1,31\)
\(\Leftrightarrow x+\frac{3x}{10}=-1,31\)
\(\Leftrightarrow10x+3x=-13,1\)
\(\Leftrightarrow13x=-13,1\Leftrightarrow x=-\frac{131}{130}\)
\(b)\left(x-\frac{1}{2}\right):\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
\(\Leftrightarrow\frac{2x-1}{2}.3+\frac{5}{7}=\frac{68}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=\frac{63}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=9\)
\(\Leftrightarrow6x-3=18\)
\(\Leftrightarrow x=\frac{7}{2}\)
Dễ mà
a, \(\left(4\frac{46}{65}+x\right).1\frac{1}{2}=5,75\)
\(\left(4\frac{46}{65}+x\right)=5,75:1\frac{1}{2}\)
\(\left(4\frac{46}{65}.x\right)=4\)
\(x=4:4\frac{46}{65}\)
\(x=\frac{130}{153}\)
b tương tự
a. \(\frac{1}{5}=0,2\)
\(\Rightarrow|x|=-0,2\)
b.\(\frac{x+9}{15}=\frac{3}{5}\)
\(\frac{9}{15}=\frac{3}{5}\Rightarrow\frac{x+9}{15}=\frac{9}{5}\)
\(\Rightarrow x=0\)
c. \(|x|=0,75=\frac{3}{4}\)
\(|x|=\frac{3}{4}\)
\(|x|=-0,75\)
d.\(\frac{x}{169}=\frac{10^4}{x}\)
\(\frac{x}{169}=\frac{10000}{x}\)
\(\Rightarrow x=-1300\)
a) \(\frac{x}{3}\)\(-\)\(\frac{1}{8}\)\(=\)\(\frac{5}{8}\)
\(\Rightarrow\) \(\frac{x}{3}\)=\(\frac{5}{8}+\frac{1}{8}\)
\(\Rightarrow\) \(\frac{x}{3}\)\(=\frac{3}{4}\)
\(\Rightarrow\) x=3.3:4
\(\Rightarrow\) x=2,25
Vậy x=2,25
b) \(3\frac{1}{3}\).x-\(6\frac{3}{4}=3\frac{1}{4}\)
\(\Rightarrow\)\(\frac{10}{3}\).x-\(\frac{27}{4}=\frac{13}{4}\)
\(\Rightarrow\) \(\frac{10}{3}\).x=\(\frac{13}{4}+\frac{27}{4}\)
\(\Rightarrow\) \(\frac{10}{3}\).x=10
\(\Rightarrow\) x=\(10\div\frac{10}{3}\)
\(\Rightarrow\) x=3
Vậy x=3
Ủng hộ mik nha mọi người !
Ta có : \(\frac{x}{3}-\frac{1}{8}=\frac{5}{8}\)
\(\Leftrightarrow\frac{x}{3}=\frac{5}{8}-\frac{1}{8}\)
\(\Leftrightarrow\frac{x}{3}=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{1}{2}.\frac{1}{3}=\frac{1}{6}\)
