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a) ( 1/2-1/3-1/6).(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10
0.(1/2+2/3+3/4+...+2017/2018) + 3/4.x = 9/10
0+3/4.x = 9/10
3/4.x = 9/10
x = 9/10: 3/4
x = 6/5
b) x + ( 3/1.3+3/3.5+...+3/13.15) = 11/5
x + 3/2. ( 1-1/3 + 1/3 - 1/5 + ...+ 1/13 - 1/15) = 11/5
x + 3/2. ( 1-1/15) = 11/5
x + 3/2.14/15 = 11/5
x + 7/5 = 11/5
x = 11/5 - 7/5
x = 4/5
x . 6/5 + x : 5/42 + x + x : 5/3 = 28
x. 6/5 + x . 42/5 + x + x . 3/5 = 28
x . ( 6/5 + 42/5 + 1 + 3/5 )=28
x . 56/5 = 28
x = 28 : 56/5
x = 5/2
a) (x + 1,2) : 2,5 = 5
x + 1,2 = 5 . 2,5
x + 1,2 = 12,5
x = 12,5 - 1,2
x = 11,3
Vậy x = 11,3
\(b)4,25.x=53,38\)
\(x=53,38:4,25\)
\(x=12,56\)
Vậy x = 12,56
\(c)x.\frac{1}{2}+\frac{3}{4}=1\)
\(x.\frac{1}{2}=1-\frac{3}{4}\)
\(x.\frac{1}{2}=\frac{1}{4}\)
\(x=\frac{1}{4}:\frac{1}{2}\)
\(x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
\(d)\frac{2}{7}+\frac{5}{7}:x=5-\frac{1}{7}\)
\(\frac{2}{7}+\frac{5}{7}:x=\frac{34}{7}\)
\(\frac{5}{7}:x=\frac{34}{7}-\frac{2}{7}\)
\(\frac{5}{7}:x=\frac{32}{7}\)
\(x=\frac{5}{7}:\frac{32}{7}\)
\(x=\frac{5}{32}\)
Vậy \(x=\frac{5}{32}\)
e) x - 2448 : 24 = 102
x - 102 = 102
x = 102 + 102
x = 204
Vậy x = 204
a)\(\frac{24}{x}\times\frac{1}{4}=\frac{2}{5}\)
\(\frac{24}{x}=\frac{2}{5}:\frac{1}{4}\)
\(\frac{24}{x}=\frac{8}{5}\)
\(x=24:\frac{8}{5}\)
\(x=15\)
X = 240