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a, \(4x^3+12=120\)
\(\Leftrightarrow4x^3=120-12\)
\(\Leftrightarrow4x^3=108\)
\(\Leftrightarrow x^3=108:4\)
\(\Leftrightarrow x^3=27\)
\(\Leftrightarrow x=3\)
b, \(3.2^x-3=45\)
\(\Leftrightarrow3.2^x=45+3\)
\(\Leftrightarrow3.2^x=48\)
\(\Leftrightarrow2^x=48:3\)
\(\Leftrightarrow2^x=16\)
\(\Leftrightarrow x=4\)
Câu c, bạn làm tương tự nha !
a, 4x^3 + 12 = 120 b,3.2^x-3=45 c, 1500:[(30x +40):x]=30
4x^3=120-12 3.2^x =45+3 (30x +40):x =1500:30
4x^3=108 3.2^x =48 (30x +40):x = 50
x^3=108:4 2^x =48:3 30x:x+40:x = 50
x^3=27 2^x =16 30+40:x=50
=> x^3= 3^3 2^x =2^4 40:x=50-30
=> x = 3 => x =4 40:x= 20
=>x=40:20
=>x=20 ( câu c tui có làm sai thì đừng trách nhé )
a: Ta có: \(\left[\left(6x-39\right):3\right]\cdot28=5628\)
\(\Leftrightarrow\left(6x-39\right):3=201\)
\(\Leftrightarrow6x-39=603\)
\(\Leftrightarrow6x=642\)
hay x=107
b: Ta có: \(4x^3+12=120\)
\(\Leftrightarrow4x^3=108\)
\(\Leftrightarrow x^3=27\)
hay x=3
c: Ta có: \(1500:\left[\left(30x+40\right):x\right]=30\)
\(\Leftrightarrow\left(30x+40\right):x=50\)
\(\Leftrightarrow30x+40=50x\)
hay x=-2
\(4x^3+12=120\)
\(\Rightarrow4x^3=108\)
\(\Rightarrow x^3=108:4=27=3^3\)
\(\Rightarrow x=3\)
\(3.2^x-3=45\)
\(\Rightarrow3.2^x=48\)
\(\Rightarrow2^x=16=2^4\Rightarrow x=4\)
\(1500:\left[\left(30x+40\right):x\right]=30\)
\(\Rightarrow\left(30x+40\right):x=50\)
\(\Rightarrow30x:x+40:x=50\)
\(\Rightarrow30+40:x=50\)
\(\Rightarrow40:x=20\Rightarrow x=2\)
hung pham tien bn vào câu hỏi tương tự đi , có đấy
**** cho minh
\(\frac{30x+40}{x}=1500:30\)
\(\frac{30x+40}{x}=50\)
Suy ra 30x+40= 50.x
40= 50x- 30x
40= 20x
x=40:20=2
\(1500:\frac{30x+40}{x}=30\)
\(\frac{30x+40}{x}=1500:30\)
\(\frac{30x+40}{x}=50\)
\(\Rightarrow30x+40=50x\)
\(30x+40-50x=0\)
\(40+\left(30x-50x\right)=0\)
\(40-20x=0\)
\(20\left(20-x\right)=0\)
\(\Rightarrow20-x=0\)
\(x=20\)
Vậy x = 20
1500: [(30x + 40) : x]=30
=>(30x + 40): x = 1500 : 30
=>30x : x+ 40:x=50
=> 30 + 40 :x=50
=> 40 :x=50-30
=> 40:x=20
=>x=40:20
=>x=2
: [(30x + 40) : x] = 30(2x - 15)5 = (2x - 15)3
=>(30x+40):x=1500 : 30=50
40:x = 50-30
40:x=20
x=2
\(1500:\left[\left(30x+40\right):x\right]=30\)
\(\Leftrightarrow\left(30x+40\right):x=50\)
\(\Leftrightarrow30x+40=50x\)
\(\Leftrightarrow50x-30x=40\)
\(\Leftrightarrow20x=40\)
\(\Leftrightarrow x=2\)
Vậy ..
1500 : [ ( 30x + 40 ) : x ] = 30
[ ( 30x + 40 ) : x ] = 1500 : 30
[ ( 30x + 40 ) : x ] = 50
( 30x + 40 ) = 50 . x
( 30x + 40 ) = 50x
40 = 50x - 30x
40 = 20x
x = 40 : 20
x = 2
Vậy x = 2
1500:[(30x+40):x]=30
=>(30x+40):x=1500:30
=>30x:x+40:x=50
=>30+40:x=50
=>40:x=50-30
=>40:x=20
=>x=40:20
=>x=2
x = 3
x = 4
x = 2
nha bạn